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3 years ago

A cupcake recipe designed to produce 28 cupcakes calls for 360 grams of flour Determine the quantity of flour that would be

2 answers:

4 0

Since the 360 grams of flour are used to produce 28 cupcakes , thus the quantity (mass) of flour is said to be distributed equally on all 28 cupcakes thus, every cupcake requires 360/28 grams of flour which is equal to 12.8571 grams.

By the same logic the 32 cupcakes would have a different amount of flour distributed equally amongst all 32 cupcakes thus the quantity required is equal to 32 times required to prepare 1 cupcake , we conclude that the mass needed is equal to 32 x 12.8571 = 411.4272 grams of flour.
If you still have any questions i’ll be there to answer. ♥️♥️

Novosadov [1.4K]3 years ago

3 0

Answer:24888.8g

Explanation: 28cupcakes calls 360g

32 cupcakes calls ???

28x32=896 cupcakes

896/360= 2.4888888g

In four decimal place = 24888.8grams

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How are passengers affected when a moving bus is stopped suddenly? Explain with reason.<br>

Mademuasel [1]

Answer:

When a moving bus stops suddenly, the passenger are pushed forward because of the inertia of the passengers. ... Because the lower part of the body comes to rest with the bus while the upper part tends to continue its motion due to inertia.

Explanation :

The passengers in a bus tend to fall backward when it starts suddenly due to inertia as the passengers tend to remain in the state of rest while the bus starts to move. When the bus stops suddenly, people fall forward because their inertia as they are in state of motion even when the bus has come to rest.

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2 years ago

1. A horizontal force of 50 N is applied to push a desk 40 m across a

dybincka [34]

Work = N × m = 50 x 40 = 2000 J

4 0

3 years ago

Mark pushes his broken car 140 m down the block to his friend's house. He has to exert a 160 N horizontal force to push the car

sesenic [268]

The thermal energy used by the tires is 1.14 J.

Here, the thermal energy used will be the work done by Mark.

Given,

Distance = 140 m

Force exerted = 160 N

Thermal energy = ?

We know,

Work = force * displacement

But here the thermal energy of tires is asked.

In this question, the thermal energy used is the energy consumed to do the work.

So, using the formula of work we can find the thermal energy.

W = 160 / 140 = 1.14 J

Therefore the thermal energy used by the tires is 1.14J

To learn more about thermal energy, refer: brainly.com/question/1687193

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3 0

1 year ago

A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho

Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

$\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f$

There is no kinetic energy in the initial state, nor potential energy in the end,

$mgh+0=0+KE_f$

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

$mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)$

The inertia of the bodies is given by the equation,

$I=\frac{m(R_1^2+R^2_2)}{2}$

$I=\frac{2(0.2^2+0.1^2)}{2}$

$I=0.05Kgm^2$

On the other hand the angular velocity is given by

$\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s$

Replacing these values in the equation,

$(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2$

Solving for h,

$h=2.86m$

5 0

3 years ago

Car A is accelerating in the direction of its motion at the rate of 3 ft /sec2. Car B is rounding a curve of 440-ft radius at a

Katena32 [7]

Answer:

Incomplete question

Check attachment for the diagram of the problem.

Explanation:

The acceleration of the car A is given as

a=3ft/s²

Car B is rounding a curve of radius

r=440ft

Car B is moving at constant speed of Vb=30mi/hr.

Car A reach a speed of 45mi/hr

Note, 1 mile = 5280ft

And 1 hour= 3600s

Then

Va=45mi/hr=45×5280/3600

Va=66ft/s

Also,

Vb=30mi/hour=30×5280/3600

Vb=44ft/s

Now,

a. Let write the relative velocity of car B, relative to car A

Vb = Va + Vb/a

Then,

Using triangle rule, because vectors cannot be added automatically

Vb/a²= Vb²+Va²-2Va•VbCosθ

From the given graphical question the angle between Va and Vb is 60°.

Vb/a²=44²+66² - 2•44•66Cos60

Vb/a²=1936+ 4356 - 5808Cos60

Vb/a² = 3388

Vb/a = √3388

Vb/a = 58.21 ft/s

The direction is given as

Using Sine Rule

a/SinA = b/SinB = c/SinC

i.e.

Va/SinA = Vb/SinB = (Vb/a)/SinC

66/SinA = 44/SinB = 58.21/Sin60

Then, to get B

44/SinB = 58.21/Sin60

44Sin60/58.21 = SinB

0.6546 = SinB

B=arcsin(0.6546)

B=40.89°

b. The acceleration of Car B due to Car A.

Let write the relative acceleration of car B, relative to car A.

Let Aa be acceleration of car A

Ab be the acceleration of car B.

Ab = Aa + Ab/a

Given the acceleration of car A

Aa=3ft/s²

Then to get the acceleration of car B, using the tangential acceleration formular

a = v²/r

Ab = Vb²/r

Ab = 44²/440

Ab = 4.4ft/s²

Using cosine rule again as above

Ab/a²= Aa²+Ab² - 2•Aa•Ab•Cosθ

Ab/a²= 3²+4.4²- 2•3•4.4•Cos30

Ab/a²= 9+19.36 - 22.863

Ab/a² = 5.497

Ab/a = √5.497

Ab/a = 2.34ft/s²

To get the direction using Sine rule again, as done above

Using Sine Rule

a/SinA = b/SinB = c/SinC

i.e.

Aa/SinA = Ab/SinB = (Ab/a)/SinC

3/SinA = 4.4/SinB = 2.34/Sin30

Then, to get B

4.4/SinB = 2.34/Sin30

4.4Sin30/2.34 = SinB

0.9402 = SinB

B=arcsin(0.9402)

B=70.1°

Since B is obtuse, the other solution for Sine is given as

B= nπ - θ. , when n=1

B=180-70.1

B=109.92°

4 0

3 years ago