Answer:
A) The wave that travels through the rail reaches the microphone first.
B) separation in time between the arrivals of the two pulses is 0.01539 seconds.
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
4
Explanation:
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
= Mass of Earth
= Mass of Moon
r = Distance between Earth and Moon
Old gravitational force
![F_o=\dfrac{Gm_1m_2}{r^2}](https://tex.z-dn.net/?f=F_o%3D%5Cdfrac%7BGm_1m_2%7D%7Br%5E2%7D)
New gravitational force
![F_n=\dfrac{Gm_1m_2}{(\dfrac{1}{2}r)^2}](https://tex.z-dn.net/?f=F_n%3D%5Cdfrac%7BGm_1m_2%7D%7B%28%5Cdfrac%7B1%7D%7B2%7Dr%29%5E2%7D)
Dividing the equations
![\dfrac{F_n}{F_o}=\dfrac{\dfrac{Gm_1m_2}{(\dfrac{1}{2}r)^2}}{\dfrac{Gm_1m_2}{r^2}}\\\Rightarrow \dfrac{F_n}{F_o}=\dfrac{\dfrac{Gm_1m_2}{\dfrac{1}{4}r^2}}{\dfrac{Gm_1m_2}{r^2}}\\\Rightarrow \dfrac{F_n}{F_o}=4](https://tex.z-dn.net/?f=%5Cdfrac%7BF_n%7D%7BF_o%7D%3D%5Cdfrac%7B%5Cdfrac%7BGm_1m_2%7D%7B%28%5Cdfrac%7B1%7D%7B2%7Dr%29%5E2%7D%7D%7B%5Cdfrac%7BGm_1m_2%7D%7Br%5E2%7D%7D%5C%5C%5CRightarrow%20%5Cdfrac%7BF_n%7D%7BF_o%7D%3D%5Cdfrac%7B%5Cdfrac%7BGm_1m_2%7D%7B%5Cdfrac%7B1%7D%7B4%7Dr%5E2%7D%7D%7B%5Cdfrac%7BGm_1m_2%7D%7Br%5E2%7D%7D%5C%5C%5CRightarrow%20%5Cdfrac%7BF_n%7D%7BF_o%7D%3D4)
The ratio is ![\dfrac{F_n}{F_o}=4](https://tex.z-dn.net/?f=%5Cdfrac%7BF_n%7D%7BF_o%7D%3D4)
The new force would be 4 times the old force
Answer:
![\theta=12.19^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D12.19%5E%7B%5Ccirc%7D)
Explanation:
Given that
The speed of the airplane ,v= 142 m/s
The speed of the air ,u = 30 m/s
Lets take angle make by airplane from east direction towards north direction is θ .
Now by using diagram ,we can say that
![sin\theta =\dfrac{u}{v}](https://tex.z-dn.net/?f=sin%5Ctheta%20%3D%5Cdfrac%7Bu%7D%7Bv%7D)
Now by putting the values in the above equation we get
![sin\theta =\dfrac{30}{142}](https://tex.z-dn.net/?f=sin%5Ctheta%20%3D%5Cdfrac%7B30%7D%7B142%7D)
![sin\theta=0.21](https://tex.z-dn.net/?f=sin%5Ctheta%3D0.21)
![\theta=12.19^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D12.19%5E%7B%5Ccirc%7D)
Therefore the angle will be 12.19° .