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MAXImum [283]
4 years ago
5

WILL MARK BRAINLIEST

Chemistry
1 answer:
serious [3.7K]4 years ago
4 0

Answer:

option b

Explanation:

556+3810

=4366

=4.366*10^3

Hope it helps

Pls mark as brainliest

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3 years ago
What is the oh- in a solution with a poh of 5.71
Rudik [331]

Answer:- The hydroxide ion concentration of the solution is 1.95*10^-^6 .

Solution:- The formula used to calculate pOH from hydroxide ion is:

pOH=-log[OH^-]

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3 0
3 years ago
1)
nataly862011 [7]

Answer:

A

Explanation:

a is the right answer abi

5 0
3 years ago
Calculate the ph of a 0.0075 m ca(oh)2 solution.
Aleksandr [31]
Ca(OH)₂ = Ca²⁺ + 2OH⁻

[OH⁻]=2c{Ca(OH)₂}

pH=14+lg[OH⁻]

pH=14+lg(2c{Ca(OH)₂})

pH=14+lg(2*0.0075)=12.18
3 0
3 years ago
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