Question

Complete the table using the balanced chemical equation

Answer 1

Answer:

First line of the table:

FeS: 1.2mol  

$O_{2}$: 1.8moles

FeO: 1.2moles

$SO_{2}$: 1.2moles

Second line of the table:

FeS: 5.2mol  

$O_{2}$: 7.8moles

FeO: 5.2moles

$SO_{2}$: 5.2moles

Explanation:

1. Take as reference the balanced chemical equation:

$_{2}FeS(s)+_{3}O_{2}(g)=_{2}FeO(s)+_{2}SO_{2}(g)$

2. Take the first quantity given in the table to calculate the quantities of the other compounds using stoichiometry:

- Calculate the number of moles of $O_{2}$:

$1.2molesFeS*\frac{3molesO_{2}}{2molesFeS}=1.8molesO_{2}$

- Calculate the number of moles of FeO:

$1.2molesFeS*\frac{2molesFeO}{2molesFeS}=1.2molesFeO$

-Calculate the number of moles of $SO_{2}$:

$1.2molesFeS*\frac{2molesSO_{2}}{2molesFeS}=1.2molesSO_{2}$

3. Take the second quantity given in the table to complete the other quantities using stoichiometry:

- Calculate the number of moles of FeS:

$5.2molesSO_{2}*\frac{2molesFeS}{2molesSO_{2}}=5.2molesFeS$

- Calculate the number of moles of $O_{2}$:

$5.2molesSO_{2}*\frac{3molesO_{2}}{2molesSO_{2}}=7.8molesO_{2}$

- Calculate the number of moles of FeO:

$5.2molesSO_{2}*\frac{2molesFeO}{2molesSO_{2}}=5.2molesFeO$

Answer 2

For 1.2 mol FeS, 1.8 mol O2, 1.2 mol FeO, 1.2 mol SO2
For 5.2 mol SO2, 5.2 mol FeS, 7.8 mol O2, 5.2 mol FeO