Which of the following is a pure substance?
2 answers:
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Answer:
Explanation:
First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=
Explanation:
General electronic configuration for the given groups are as follows.
For 4A(14) :
This means that there are 4 unpaired electrons in group 4A(14).
For 7A(17) :
So, there are 7 unpaired electrons present in group 7A(17).
For 1A(1) :
Hence, there is only one unpaired electron present in group 1A(1).
For 6A(16) :
So, there are 6 unpaired electrons present in group 6A(16).