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ANEK [815]
3 years ago
10

A jet fighter flying at 300 m/s (just below the speed of sound) makes a turn of radius 1.85 km. (a) what is its centripetal acce

leration in gs?
Physics
1 answer:
777dan777 [17]3 years ago
7 0
centripetal acceleration can be determined using the following equation;
a = v² / r
a= centripetal acceleration
v = velocity 
r = radius
substituting the values in the equation,
a = (300 m/s)*(300m/s) / (1.85 *1000) m
   = 48.64 ms-²
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Answer:

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Explanation:

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Using Snell's Law we can write:

n_1\sin(\theta_1)=n_2\sin(\theta_2)

\implies \sin(\theta_1)=\frac{n_2}{n_1}\sin(\theta_2),

Let's approximate the index of refraction of the air (medium 1 in the picture) to 1.

We thus have:

\sin(\theta_1)=n_2\sin(\theta_2)=1.333\sin(47)

\implies\theta_1=\arcsin[n_2\sin(\theta_2)]=\arcsin[1.333\sin(47)]\approx 77.13. Calling \alpha the actual angle of elevation, we get from the picture that \alpha=90-77.13=12.97

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Answer:

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Explanation:

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Explanation:

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