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3 years ago

Please sketch a propanol

Chemistry

2 answers:

Law Incorporation [45]3 years ago

5 0

Could u give details about the propanol?

Alex787 [66]3 years ago

5 0

The formula for propanol:
* $C_{3}H_{7}OH$
* $CH_{3} CH_{2} CH_{2}OH$

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How many moles are in 1.20 times 10^25 atoms of phosphorus

Stels [109]

19.927 moles are in 1.20 times $10^{25}$ atoms of phosphorus.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others.

1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .

Moles= $\frac{Atoms}{\;Avogadro's \;number }$

Moles= 1.20 X $10^{25}$ atoms ÷ 6.022 X $10^{23}$

= 19.927

Hence, 19.927 moles are in 1.20 times $10^{25}$ atoms of phosphorus.

Learn more about moles here:

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1 year ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

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2 years ago

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3 years ago

I need to know the independent variable and the dependent variable and control variable

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