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Sedaia [141]
3 years ago
14

To understand the nature of electric fields and how to draw field lines. Electric field lines are a tool used to visualize elect

ric fields. A field line is drawn beginning at a positive charge and ending at a negative charge. Field lines may also appear from the edge of a picture or disappear at the edge of the picture. Such lines are said to begin or end at infinity. The field lines are directed so that the electric field at any point is tangent to the field line at that point.

Physics
1 answer:
Brrunno [24]3 years ago
7 0

Explanation:

The electric field is defined as the change in the properties of space caused by the existence of a positively (+) or negatively (-) charged particle. The electric field can be represented by infinitely many lines from a particle, and those lines never intersect each other. Depending on the type of charge we can see different cases:

  • Let's say we have a <u>positive charge alone (</u>image 1)<u>.</u> The field lines are drawn from the centre of the particle outwards to infinity (in other words, they disappear from the edge of the picture). Meaning the direction of the electric field points outwards the particle.
  • For a <u>negative charge alone </u>(image 2)<u>,</u> the lines come from infinity to the centre, and point towards the particle (i.e. lines appear from the edge of the picture).

Let's see what happens if we have two charges together:

  • <u>Two positive charges</u> (image 3): Since the charges are of the same type (positive), the particles repel each other. Then the field lines will avoid each other so they do not join. The charge is positive, so lines point outwards.
  • <u>Two negative charges</u> (image 4): Again, the charges are both negative, so they repel. But they are negative, so the field points inwards.
  • <u>Negative and positive charges</u> (image 5): They are different charges, so the force between them is attractive. This causes the field lines from both to join. They go out of the positive and come into the negative particle.

Image 6:

The lines are passing through infinite points of the space. If we choose a certain point and measure the electric field, we can see to which direction the electric field points. This is the direction of the electric field vector. It does not matter which point we choose; the electric field vector touches the field line only at this point, which means it is tangent to the field line.

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3 years ago
A loop of area 0.100 m² is oriented at a 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0 degree
MatroZZZ [7]

The resulting change in the magnetic flux is =0.013Wb

what is magnetic flux?

Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. It provides the measurement of the total magnetic field that passes through a given surface area

Given:

At degree =15.5°,magnetic flux=magnetic field=0.500T

At degree=45.0°, magnetic field=0.500T

Magnetic flux=magnetic field ×Area×cos(angle)

magnetic flux (1) = 0.500×0.1×cos(15.5)

= 0.048

magnetic flux (2) = 0.500×0.1×cos(45)

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learn more about magnetic flux from here: brainly.com/question/28179515

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2 years ago
True or false? An object at rest has an instantaneous acceleration of zero.
Tpy6a [65]
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3 years ago
What is the kinetic energy of an object with a mass of 50kg and is and it is traveling at a rate of 60m/s.
liq [111]

Answer:

90,000 J

Explanation:

Kinetic energy can be found using the following formula.

KE=\frac{1}{2}mv^2

where <em>m </em>is the mass in kilograms and <em>v</em> is the velocity in m/s.

We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.

<em>m</em>=50

<em>v</em>=60

Substitute these values into the formula.

KE=\frac{1}{2}*50*60^2

First, evaluate the exponent: 60^2. 60^2 is the same as multiplying 60, 2 times.

60^2=60*60=3,600

KE=\frac{1}{2}*50*3,600

Multiply 50 and 3,600

KE=\frac{1}{2}*180,000

Multiply 1/2 and 3,600, or divide 3,600 by 2.

KE=90,000

Add appropriate units. Kinetic energy uses Joules, or J.

KE=90,000 Joules

The kinetic energy of the object is 90,000 Joules

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Answer:

+70 km/h north

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