Answer:
the result 
= g .The correct answer is d
Explanation:
For this problem let's start by finding the center of mass of objects
= 1 / M ∑ 
we apply this equation to our case
M = m + 2m + 3m
M = 6m
x_{cm} = 1 / 6m (x₁ m + x₂ 2m + x₃ 3m)
x_{cm} = 1/6 (x₁ + 2 x₂ + 3x₃)
We apply Newton's second law to this center of mass
dp / dt = M a
d (M v_{cm}) / dt = M a
let's find the speed of the center of mass
v_{cm} = 1 / 6m (m v + 2m 0 - 3m v)
v_{cm} = ⅓ v
M d v_{cm}/ dt = M a
d v_{cm} / dt = a
at the center of mass the external force of the system is applied, which is the force of gravity
dv_{cm} / dt = g
therefore the result
a = g
The correct answer is d
I ain’t never seen two pretty best friends
Considering Conservation of Momentum, the momentum
before and after must remain the same:
so:
before:
Answer:
Explanation:
Force of friction acting on the body = μ mg cosθ
= .4 x 70 x 9.8 x cos30
= 237.63 N
component of weight = mgsinθ
= 70 x 9.8 x sin30
= 343 N
Net upward force = 600 - mgsinθ - μ mg cosθ
= 600 - 343 - 237.63
= 105.37 N
acceleration in upward direction = 105.37 / 70
= 1.5 m /s²
s = ut + 1/2 a t²
= 0 + .5 x 1.5 x 3²
= 6.75 m .
Answer:
Explanation:
Given
Pressure, Temperature, Volume of gases is
Let P & T be the final Pressure and Temperature
as it is rigid adiabatic container therefore Q=0 as heat loss by one gas is equal to heat gain by another gas
where Q=heat loss or gain (- heat loss,+heat gain)
W=work done by gas
change in internal Energy of gas
Thus from 1 & 2 we can say that
where 
and 
