Answer:
The pressure will be transmitted equally to all other parts of the confined fluid causing a general increase in pressure throughout the container.
Explanation:
This is in line with pascal's law of pressure which states that the pressure exerted on a given mass of fluid is transmitted undiminished to other parts of the fluid.
Answer:
<h2> 27m/s</h2>
Explanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s
Answer:
H = 34.43 m
Explanation:
Given that,
Initial speed of the object, u = 30 m/s
The angle of projection, ![\theta=60^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D60%5E%7B%5Ccirc%7D)
We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.
![H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m](https://tex.z-dn.net/?f=H%3D%5Cdfrac%7Bu%5E2%5Csin%5E2%5Ctheta%7D%7B2g%7D%5C%5C%5C%5CH%3D%5Cdfrac%7B%2830%29%5E2%5Ctimes%20%5Csin%5E2%2860%29%7D%7B2%5Ctimes%209.8%7D%5C%5C%5C%5CH%3D34.43%5C%20m)
So, the maximum height reached by the object is 34.43 m.
I think answer should be d. Please give me brainlest let me know if it’s correct