The given question is incomplete. The complete question is:
The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:
A. 
B. 
C. 
D.
Answer: A.
: decreases
B.
: decreases
C.
: no change
D.
: increases
Explanation:
Entropy is defined as the randomness of the system.
Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.
In reaction
, as gaseous reactant is changed to solid product, entropy decreases.
In reaction
, as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.
In reaction
, as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.
In reaction
, as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.
In the given situation, the reaction is-
NO + H2 ↔ Products
The rate of the reaction can be expressed (in terms of the decrease in the concentration of the reactants) as-
Rate = -dΔ[NO]/dt = -dΔ[H2]/dt
Now, if the concentration of NO is decreased there will be fewer molecules of the reactant NO which would decrease the its collision with H2. As a result the rate of the forward reaction would also decrease.
Ans) A decrease in the concentration of nitrogen monoxide decreases the collisions between NO and H2 molecules. the rate of the forward reaction then decreases.
Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
Answer:
if the heat of reaction is positive, the reaction is said to be endothermic; if negative, exothermic.
Explanation:
hope this helps
i am so sorry if this is the wrong answer
Answer: b.) they tend to lose electrons to gain stability
Explanation: