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JulsSmile [24]
3 years ago
14

For every 3 tickets you sell, your friend sells 4. You sell a total of 12 tickets. How many does your friend sell?

Mathematics
1 answer:
sweet [91]3 years ago
4 0

the friend sold 16 tickets

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A. How much will LaToya pay in taxes for the year? Show your work.
marusya05 [52]
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8 0
2 years ago
Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).
kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Finding the lengths of the segments

For AB

AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14

For BC

BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28

For CD

CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12

For DA

DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0
3 years ago
The officer stepped off 20 paces from E to G. If his pace is 2 1/2 feet long. How wide was the river?
Sergeeva-Olga [200]

Answer:

The wide of river is 50\ ft

Step-by-step explanation:

In this problem we know that

Triangles DEG and DEF are congruent by ASA (Angle-Side-Angle) Congruence

therefore

EG=EF

EG=20*(2\frac{1}{2})=20*\frac{5}{2}=50\ ft

8 0
3 years ago
Surface Area of the pyramid
hichkok12 [17]

Answer:

C

Step-by-step explanation:

the total surface area of such a pyramid is the sum of 5 areas :

1 bottom square (8×8)

4 side triangles

the area of a triangle is

baseline × height / 2

now, we know the baseline of the 4 triangles, but what is their height (at least we know, all 4 have the same height, as the pyramid is totally regular) ?

the height of the side triangles is the slant height of the pyramid (the distance from the middle of a sideline to the top of the pyramid).

we get this by imagining a right-angled triangle inside the pyramid :

one leg is the inner height of the pyramid.

the second leg is the connection on the bottom square from the base of the inner height to the middle point of a sideline). this is half the length of a sideline.

and the baseline (Hypotenuse) is the slant height of the pyramid.

we can use Pythagoras

c² = a² + b²

with c being the Hypotenuse (side opposite of the 90° angle).

slant height² = 7² + (8/2)² = 49 + 4² = 49 + 16 = 65

slant height = sqrt(65) = 8.062257748... in

so, we get a areas

bottom square = 8×8 = 64 in²

a side triangle = 8×sqrt(65)/2 = 4×sqrt(65) =

= 32.24903099... in²

all 4 side triangles = 4×32.24903099... =

= 128.996124... in²

and we get as total surface area

64 + 128.996124... = 192.996124... in² ≈ 193.00 in²

8 0
1 year ago
PLEASE ANSWER QUICKLY! <br><br> Write an equation for each translation of y = |x|.<br> NUMBER 4
Leya [2.2K]
The answer is d I just did that paper mark me Brainly
3 0
2 years ago
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