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navik [9.2K]
3 years ago
12

How to convert f to c without a calculator ​

Chemistry
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

Without a calculator, there are many means to convert Celsius to Fahrenheit. Multiply the Celsius temperature by 1.8 and add 32 to get the Fahrenheit conversion With this method you get the exact temperature conversion degree.

Explanation:

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51. The radius of gold is 144 pm and the density is 19.32 g/cm3. Does elemental gold have a face-centered cubic structure or a b
Serjik [45]

Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

Its density = 19.32 g/cm³

Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

a = \sqrt{8} r

a = \sqrt{8} \times 144 pm

a = 407 pm

In a unit cell, Volume (V) = a³

V = (407 pm)³

V = 6.74 × 10⁷ pm³

V = 6.74 × 10⁻²³ cm³

Recall that:

Net no. of an atom in an FCC unit cell = 4

Thus;

density = \dfrac{mass}{volume}

density = \dfrac{ 4 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{6.74 \times 10^{-23} \ cm^3}

density d = 19.41 g/cm³

Similarly; For a  body-centered cubic structure

r = \dfrac{\sqrt{3}}{4}a

where;

r = 144

144 = \dfrac{\sqrt{3}}{4}a

a = \dfrac{144 \times 4}{\sqrt{3}}

a = 332.56 pm

In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

V  3.68 × 10⁻²³   cm³

Recall that:

Net no. of atoms in BCC cell = 2

∴

density = \dfrac{mass}{volume}

density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}

density =17.78 g/cm³

From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.

This makes the elemental gold to have a Face-centered cubic structure.

3 0
3 years ago
Which part of the atom is directly involved in chemical changes? A. the electron B. the energy levels C. the nucleus D. the char
7nadin3 [17]
The part of the atom that is involved in chemical changes is A. electron. The electrons that are in the most outer shells are called valence electrons which are easily removed or shared to form bonds. Valence electrons are related to the number of valence electrons
8 0
3 years ago
Write balanced equations for each of the processes described below. (Use the lowest possible coefficients. Omit states-of-matter
Aleks [24]

Answer:

d

Explanation:

7 0
3 years ago
a scientist finds an organism that has a single cell without a nucleus.This organism was found in pond water.In which KINGDOM do
notka56 [123]

<em>Archaea (Archaeon ): Single-celled microorganisms without nuclei and with membranes different from all other organisms. Once thought to be bacteria. </em>

<em />

<em>Unicellular organism</em>

<em>-A unicellular organism, also known as a single-celled organism, is an organism that consists of a single cell, unlike a multicellular organism that consists of multiple cells. Unicellular organisms fall into two general categories: prokaryotic organisms and eukaryotic organisms. </em>

8 0
2 years ago
Consider the balanced equation below.
kondaur [170]

The option which gives the correct mole ratios is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3 /><h3>What is Mole ratio ?</h3>

It is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

The balanced equation for given reaction is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

Molar ratio can be determined by the coefficients of the compounds in the balanced reaction

Coefficient is the number in front of the chemical compound and they are as follows

  • H₂S - 2
  • O₂ - 3
  • SO₂ - 2
  • H₂O - 2

Therefore, correct option is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

Learn more about mole ratio here ;

https://brainly.in/question/32799056

#SPJ1

6 0
1 year ago
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