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3 years ago

How to convert f to c without a calculator

Chemistry

1 answer:

nikdorinn [45]3 years ago

7 0

Answer:

Without a calculator, there are many means to convert Celsius to Fahrenheit. Multiply the Celsius temperature by 1.8 and add 32 to get the Fahrenheit conversion With this method you get the exact temperature conversion degree.

Explanation:

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How many atoms are contained in 100.0 g of mercury

Romashka [77]

3.00097 x $10^{23}$ atoms are contained in 100.0 g of mercury.

<h3>What is moles?</h3>

The mole is defined as the amount of substance that contains as many elementary entities as there are atoms in exactly 12 g of carbon-12.”

Number of moles of mercury = $\frac{mass}{molar \;mass}$

Number of moles of mercury = $\frac{100.0 g}{200.59 u}$

= 0.4985 moles

Number of moles of mercury = Number of atoms = moles of Hg x $6.02 X 10^{23}$

= 0.4985 x $6.02 X 10^{23}$

= 3.00097 x $10^{23}$ atoms.

Hence, 3.00097 x $10^{23}$ atoms are contained in 100.0 g of mercury.

Learn more about the moles here:

brainly.com/question/26416088

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5 0

2 years ago

How many grams of AgNO3 are needed to prepare a 75.00 mL solution that is 6.5% (m/v)?

FrozenT [24]

Answer:

Volume of AgNO₃ = 4.9 ml (Approx)

Explanation:

Given:

Total solution = 75 ml

Volume of AgNO₃ = 6.5%

Find:

Volume of AgNO₃

Computation:

Volume of AgNO₃ = Total solution x Volume of AgNO₃

Volume of AgNO₃ = 75 x 6.5%

Volume of AgNO₃ = 4.875

Volume of AgNO₃ = 4.9 ml (Approx)

5 0

3 years ago

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

4 0

3 years ago

What two categories are used in classifying particulate matter?

Allushta [10]

<span>The two categories for classifying particulate matter are through analysis of the intensive and extensive properties. Intensive properties are independent properties that can be measured independent of the amount of matter while extensive properties are measured dependent on the amount.</span>

3 0

3 years ago

Calculate the potential for each cell as shown below and indicate whether the metal electrode in the half-reaction opposite the

Lesechka [4]

.086567 is what I think as being a math matichian

8 0

4 years ago

How to convert f to c without a calculator ​

How to convert f to c without a calculator