Explanation:
<h3>The beam balance is a device used</h3><h3> for the determination of the mass of </h3><h3>a body under gravitation. It consists </h3><h3>of a beam supported at the centre </h3><h3>by an agate knife edge resting on a</h3><h3> support moving inside a vertical </h3><h3>pillar. The beam carries a light</h3><h3>pointer which moves over a scale.</h3>
Answer:
Q₁ = Q₂ = 8.84 x 10⁻⁹ C
Explanation:
given,
mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg
ball each other, r = 6.8 cm
Weight of the ball
F_w = m g
F_w = 1.6 x 10⁻⁴ x 9.8
F_w = 1.56 x 10⁻³ N
The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.
we have to find the horizontal component of the forces.
The length of the string,L is 35 cm so, it will be the hypotenuse.
θ be the angle made with imaginary vertical line and the string.
now,
θ = 5.57°
horizontal component of the force = ?
vertical component of force,F_v = 1.56 x 10⁻³ N


F_h = 1.52 x 10⁻⁴ N
now, each ball will be repelled by
F = 1.52 x 10⁻⁴ N
now calculation of charges

Q₁ = Q₂ because both charge are same

Q² = 7.809 x 10⁻¹⁷
Q = 8.84 x 10⁻⁹ C
hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C
Well what are you comparing or try to pair together?
Answer:
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A
Explanation:
Let the depth of each section is h.
That means the real depth for each section is h.
Apparent depth is liquid A is 7 cm.
Apparent depth in liquid B is 6 cm.
Apparent depth in liquid C is 5 cm.
by the formula of the refractive index
n = real depth / apparent depth
where, n is the refractive index of the liquid.
For liquid A:
.... (1)
For liquid B:
..... (2)
For liquid C:
..... (3)
By comparing all the three equations
nc > nB > nA
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A