According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first
2 answers:
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Answer:
Explanation:
Given that,
Radius of the circular loop, r = 10 cm = 0.1 m
Current flowing in the loop, I = 3.6 A
Uniform magnetic field, B = 12 T
To find,
The magnetic dipole moment of the loop.
Solution,
Let M is the magnitude of magnetic dipole moment of the loop. We know that the product of current flowing and the area of cross section. Its formula is given by :
A is the area of circular wire
Therefore, the magnetic dipole moment of the loop is . Hence, this is the required solution.