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balandron [24]
3 years ago
12

Which of Newton’s Laws explains why an object originally moving in a circular path will continue in a straight line path if the

centripetal force is reduced to zero?
Newton's 1st Law
Newton’' 2nd Law
Newton's 3rd Law
Newton's Law of Gravitation
Physics
1 answer:
Andreas93 [3]3 years ago
6 0

When object is moving in circular path then if suddenly its force reduced to zero then it will move to straight line

This is defined by Newton's First Law

So as per first law of Newton we can say

When there is no net force on an object then it will continue its state of motion in its original state without any change in it.

This is also known as law of inertia

so correct answer will be

Newton's 1st law

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What specific structures are in electroreceptors?
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The focal length of david's lens is 60 cm. if rebecca stands in front of david at a distance of do and david perceives the posit
Makovka662 [10]

if rebecca stands in front of david at a distance of do and david perceives the position of rebecca at di, di will be +84 cm

<h3>What is focal length ?</h3>

How strongly light converges or diverges depends on an optical system's focal length, which is the inverse of optical power. A system with a positive focus length is said to converge light, whereas one with a negative focal length is said to diverge light.

focal length = +60 cm

magnification m = -0.40

focal length being positive an magnification negative.

given lens is a convex lens.

for a lens

m = di/do and 1/f = (1/di) - (1/do)di

= -0.4do1/f = (1/-0.4do) - 1/do do

= -210 cmdi = -0.4 * -210

di = +84 cm

To learn more about focal length go to - brainly.com/question/25779311

#SPJ4

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3 years ago
Read 2 more answers
A 1300 kg car traveling at 35 mph rear-ends a 1000 kg car traveling 25 mph. Just after the collision (but before the driver’s sl
guajiro [1.7K]

Answer

given,

before collision

mass of car A = m_a = 1300 kg

velocity of car A = v_a  = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b  = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

P_1 = m_av_a + m_b v_b

P_1 = 1300 \times 35+ 1000 \times 25

P_1 =70500 Kg.m/s

final momentum

P_2 = m_aV_a + m_b V_b

P_2 = 1300 \times 30+ 1000 \times 31.5

P_2 =70500 Kg.m/s

here  initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

6 0
3 years ago
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