Both of them experience the same force in magnitude due to newtons third law. however, the one with the smallest mass experiences the greater acceleration due to newtons second law (F=ma) in which a=F/m
The point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.
<h3>
Position of the third mass</h3>
m1<------(x)------> m3 <-----------(94.8 m - x)-------->m2
a point, x, where m3 experiences a zero net gravitational force due to M1 and m2;
Force on m3 due to m1 = Force on m3 due to m2
Gm1m3/d² = Gm2m3/r²
m1/d² = m2/r²
where;
- d is the distance between m1 and m3 = x
- r is the distance between m3 and m2 = 94.8 - x
m1/(x²) = m2/(94.8 - x)²
m1(94.8 - x)² = m2x²
(94.8 - x)² = (m2/m1)x²
(94.8 - x)² = (10.6/25)x²
(94.8 - x)² = 0.424x²
(94.8 - x)² = (0.651)²x²
94.8 - x = 0.651x
94.8 = 1.651x
x = 94.8/1.651
x = 57.42 m
Thus, the point where m3 experiences a zero net gravitational force due to M1 and m2 is 57.42 m.
Learn more about gravitational force here: brainly.com/question/72250
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Answer:
The gauge pressure is equal to 147 kPa.
Explanation:
The pressure exerted by fluid is given by :
Where
is density of water
h is height
So, put all the values,
or
P = 147 kPa
So, the gauge pressure is equal to 147 kPa.
