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balandron [24]
2 years ago
12

Which of Newton’s Laws explains why an object originally moving in a circular path will continue in a straight line path if the

centripetal force is reduced to zero?
Newton's 1st Law
Newton’' 2nd Law
Newton's 3rd Law
Newton's Law of Gravitation
Physics
1 answer:
Andreas93 [3]2 years ago
6 0

When object is moving in circular path then if suddenly its force reduced to zero then it will move to straight line

This is defined by Newton's First Law

So as per first law of Newton we can say

When there is no net force on an object then it will continue its state of motion in its original state without any change in it.

This is also known as law of inertia

so correct answer will be

Newton's 1st law

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A 1210 kg rollercoaster car is
ratelena [41]

Answer: 4.98 m/s

Explanation:

You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.

PEi = 0 in this case

KEi = ½mVi² = PEf+KEf = mghf + ½mVf²

½1210*8.31² = 1210*9.8*2.26 + ½1210*Vf²

½1210*Vf² = ½1210*8.31² - 1210*9.8*2.26

Vf² = 8.31² - 2*9.8*2.26 = 4.98² so Vf = 4.98m/s

3 0
3 years ago
What are possible units for impulse? Check all that apply.
Neporo4naja [7]

Units of impulse: N • s, kg • meters per second

Explanation:

Impulse is defined in two ways:

1)

Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

I=F\Delta t

where

F is the force

\Delta t is the time interval

Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are

[I] = [N][s]

So,

N • s

2)

Impulse is also defined as the change in momentum experienced by an object:

I=\Delta p

where the change in momentum is given by

\Delta p = m\Delta v

where m is the mass and \Delta v is the change in velocity.

The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are

[I]=[kg][m/s]

so,

kg • meters per second

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
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What is happening at the atomic level to give rise to the observed energy?
ziro4ka [17]
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6 0
3 years ago
A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor
xxMikexx [17]

The velocity with which the jumper leaves the floor is 5.1 m/s.

<h3>What is the initial velocity of the jumper?</h3>

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • v is the initial velocity of the jumper on the floor
  • h is the maximum height reached by the jumper
  • g is acceleration due to gravity

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

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3 0
10 months ago
HELP ASAP!!
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Answer:

This is false becuase different object weigh different

Thank you!

Explanation:

3 0
2 years ago
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