Question

How many milliliters of 50 by mass hno3 solution, with a density of 2.00 grams per milliliter are required to make 500 ml

Answer 1

Answer:

V = 331.13 mL of 50 by mass NO3 solution

Explanation:

∴ δ sln = 2.00 g/mL

∴ %m HNO3 = 50% = ( mass HNO3 / mass sln ) × 100

∴ V required sln = 500 mL

∴ δ HNO3 = 1.51 g/mL.......from literature

⇒ V sln = mass sln / δ sln = 500 mL

⇒ mass sln = (500 mL )×( 2 g/mL ) = 1000 g sln

⇒ mass HNO3 = ( 0.5 )×(1000 g) = 500 g HNO3

⇒ V HNO3 = ( 500 g HNO3 )×(ml HNO3/1.51 g ) = 331.13 mL