Ask question

Ask question

All categories

1 year ago

9

A school bus with its flashing red signals on has stopped on a non-divided highway; you must?

1 answer:

g100num [7]1 year ago

6 0

In a case whereby a school bus with its flashing red signals on has stopped on a non-divided highway then you must stop until the signal lights are no longer flashing and all passengers have cleared the roadway.

<h3>What is the function of red light in traffic rules?</h3>

The function of red light in traffic rules is to tell the other road user that they should stop for a while to tell them thaqt there is a danger.

It should be noted that In a case whereby a school bus with its flashing red signals on has stopped on a non-divided highway then you must stop until the signal lights are no longer flashing and all passengers have cleared the roadway.

Read more on the traffic here:

brainly.com/question/9380087

#SPJ1

You might be interested in

Almost all collisions are due to driver error

blondinia [14]

Answer:

Where's the questaion?

4 0

1 year ago

What type of engineer would be most likely to develop a design for cars? chemical civil materials mechanical

Andreyy89

I don’t know but good luck

4 0

2 years ago

A 0.40-m3 insulated piston-cylinder device initially contains 1.3 kg of air at 30°C. At this state, the piston is free to move.

Setler79 [48]

Answer:

(a) The Final Temperature is 315.25 K.

(b) The amount of mass that has entered 0.5742 Kg.

(c) The work done is 56.52 kJ.

(d) The entrophy generation is 0.0398 kJ/kgK.

Explanation:

Explanation is in the following attachments.

6 0

2 years ago

The acceleration of a particle is given by a = 2t − 10, where a is in meters per second squared and t is in seconds. Determine t

tensa zangetsu [6.8K]

Answer

given,

a = 2 t - 10

velocity function

we know,

$\dfrac{dv}{dt}=a$

$\dfrac{dv}{dt}=(2t-10)$

integrating both side

$\int dv =\int (2t -10) dt$

v = t² - 10 t + C

at t = 0 v = 3

so, 3 = 0 - 0 + C

C = 3

Velocity function is equal to v = t² - 10 t + 3

Again we know,

$\dfrac{dx}{dt}=v$

$\dfrac{dx}{dt}=(t^2-10t + 3)$

integrating both side

$\int dx =\int (t^2-10t + 3)dt$

$x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t + C$

now, at t= 0 s = -4

$-4 = \dfrac{0^3}{3}- 10\dfrac{0^2}{2} + 0 + C$

C = -4

So,

$x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4$

Position function is equal to $x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4$

8 0

3 years ago

If you were driving the blue Prius in the situation pictured above, explain why the red Mustang should be giver right-of -way at

Scilla [17]

Because the red mustang is at the stop sign first. It’s a 4 way intersection

6 0

3 years ago