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3 years ago

5

Some General Motors flex fuel vehicles do not use a fuel sensor to measure the percentage of ethanol in the fuel. These vehicles

use ________ as a base fuel to calculate the percentage using oxygen sensor readings.

1 answer:

Anastasy [175]3 years ago

4 0

Gasoline With 1% or less ethanol content

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A fan is to be selected to ventilate a bathroom whose

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18 000 liters

Explanation:

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3 years ago

The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas

Lilit [14]

Answer:

A) 209.12 GPa

B) 105.41 GPa

Explanation:

We are given;

Modulus of elasticity of the metal; E_m = 67 GPa

Modulus of elasticity of the oxide; E_f = 390 GPa

Composition of oxide particles; V_f = 44% = 0.44

A) Formula for upper bound modulus of elasticity is given as;

E = E_m(1 - V_f) + (E_f × V_f)

Plugging in the relevant values gives;

E = (67(1 - 0.44)) + (390 × 0.44)

E = 209.12 GPa

B) Formula for upper bound modulus of elasticity is given as;

E = 1/[(V_f/E_f) + (1 - V_f)/E_m]

Plugging in the relevant values;

E = 1/((0.44/390) + ((1 - 0.44)/67))

E = 105.41 GPa

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3 years ago

does anyone have the answers to the modern carpentry book review questions for chapter 21,22, and 23

larisa [96]

You could go on Slader and look for the book, it gives you answer keys

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3 years ago

A liquid mixture containing 0.45 mol fraction of heptane and 0.55 mole fraction ethyl benzene is fed as saturated vapor to a dis

riadik2000 [5.3K]

I think it’s c but I’m now sure so don’t count on it

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3 years ago

In this problem, we will explore how deepening the pipeline affects performance in two ways: faster clock cycle and increased st

Nataliya [291]

Answer:

a) the speed up is 1.45

b) the speed up is 1.42

Explanation:

Given

5 stage pipeline = 1 ns clock cycle

12 stage pipeline = 0.6 ns clock cycle

a) The speed up is

$speed-upx_{pipeline} =\frac{CPI_{unpipelined} }{CPI_{pipelined} } (\frac{cycle-time_{unpipelined} }{cycle-time_{pipelined} } )$ (eq. 1)

The CPIpipelined is

$CPI_{pipelined} =CPI_{ideal} +average-stall-cycle/instructions$ (eq. 2)

The execution time is

$execution-time=instruction*CPI_{pipelined} *cycle-time_{unpipelined}$ (eq. 3)

The CPI for 5-stage pipeline is

CPI = 6/5

cycle time = 1 s

The CPI for 12-stage pipeline is

CPI = 11/8

cycle time = 0.6 s

Replacing values in equation 1

$speed-up_{pipeline} =\frac{I*\frac{6}{5}*1 }{I*\frac{11}{8}*0.6 } =\frac{1.2}{1.375*0.6} =1.45$

b) The equation for CPI instruction in 5-stage is

$CPI_{5} =CPI_{time} +instructions-of-5-stage*cycletime*number-of-cycles=\frac{6}{5} +(\frac{20}{100} )*0.05*2=1.22$

For CPI instruction in 12-stage is

$CPI_{12} =\frac{11}{8} +(\frac{20}{100} )*0.05*5=1.43$

The speed up is using the equation 1

$speed-up=\frac{1*1.22*1}{1*1.43*0.6} =1.42$

3 0

3 years ago