R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
=> The total numbers of cylinders on the engine.
=> Total number of lobes in the cam ring.
=> The direction at which the cam ring rotates.
Explanation:
A cam is a kind of ring and a device that is being used in engines. One or the main purpose of using cams in engines us because it helps in the change or transformation of the rotational movement of the engine to a translational one. Instead of using a cam ring, a cam roller can be used in place.
There are three things that can be used to to determine the speed of cam ring speed and they are given below as;
=> The total numbers of cylinders on the engine.
=> The Total number of lobes in the cam ring.
=> The direction at which the cam ring rotates.
Answer:
First we must know the efficiency of the gearbox in which energy is lost by friction between its components, we divide this efficiency by the nominal power and find the real power.
With this value knowing the speed of rotation of the gearbox we select an engine that has a power just above.
Also keep in mind that the motor torque must be greater than the resistance offered by the gearbox and the 0.5Kw machine
Answer:
Revoked
Explanation:
Your driver license will be revoked if you race another driver on a public road, commit a felony using a motor vehicle, or are found guilty of reckless driving three times in one year.
Answer:
a)Cycle time = 2.37 min
b)Numbers of workers =21
c)Stations on the line =24
Explanation:
Given that
Total work content time(TWC) = 50 min
Production rate Rp= 24 units/hr
manning level will be close =1.5
Line balancing efficiency =0.94
a)
Cycle time
Cycle time = 2.37 min
b)
Numbers of workers ,W
W= 21
Numbers of workers =21
c)
Stations on the line(n)
Lets find service time Ts
Ts = Cycle time - Time for repositioning
Ts = Tc- Tr
Ts= 2.37 - 9/ 60 min
Ts= 2.22 min
We know that efficiency
n=23.94 ⇒n=24
n=24
Stations on the line =24
