Answer:
B i think
Explanation:Hope it helps:)
Answer:
8 μC
Explanation:
By definition, current is the rate of change of charge, so we can write the following equation for current I:
I = ΔQ / Δt
As charge must be conserved, all the charge carried by the current must add to the charge on the plates of the capacitor, so we can finf this incremental charge as follows:
ΔQ = I* Δt (assuming that current remains constant during the charging process)
⇒ ΔQ = 3 A* 2 μsec = 3 coul/sec*2 μsec = 6 μC
As the initial charge must be conserved also, the magnitude of the net electric charge of the capacitor must be as follows:
Qnet = Q₀+ ΔQ = 2 μC + 6 μC = 8 μC
Answer:
Tech B
Explanation:
Horsepower (hp) refers to a unit of measurement of power in respect of the output of engines or motors.
Horsepower is the common unit of power. It indicates the rate at which work is done.
The formula
, where rpm is the engine speed, T is the torque, and 5,252 is radians per second.
So,
Tech B is correct
Answer:
a) The additional time required for the truck to stop is <u>8.5 seconds</u>
b) The additional distance traveled by the truck is <u>230.05 ft</u>
Explanation:
Since the acceleration is constant, the average speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for v0:
0.75v0 * 8.5 = 690
v0 = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 / 2 = 54.12 ft/s
We can now use the following equation to solve for acceleration:


a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds
Total distance traveled:

0 - 108.24^2 = 2 * (-6.367) * s
solving for s we get total distance traveled = 920.05 ft
Additional Distance Traveled: 920.05 - 690 = 230.05 ft