3 years ago

How much work is done by the gravitational force when a 265-kg pile driver falls 2.80m?

Physics

1 answer:

sp2606 [1]3 years ago

6 0

Answer:

i dont know why are u asking me

Explanation:

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A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat make

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Answer:

6.136 mm

Explanation:

given,

frequency emitted by the bat = 5.59 x 10⁴ Hz

speed of sound = 343 m/s

smallest insect bat can hear will be equal to the wavelength of the sound the bat make.

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{343}{5.59\times 10^4}$

$\lambda = 6.136\times 10^{-3}}$

λ = 6.136 mm

so, the smallest size of insect that bat can hear is equal to 6.136 mm

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The light rays in the illustration below do not properly focus at the focal point. this problem occurs with?

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3 years ago

What is the total entropy change if a 0.280 efficiency engine takes 3.78E3 J of heat from a 3.50E2 degC reservoir and exhausts i

babymother [125]

Answer:

$\Delta S=1.69J/K$

Explanation:

We know,

$\eta=1-\frac{T_2}{T_1}=1-\frac{Q_2}{Q_1}$ ..............(1)

where,

η = Efficiency of the engine

T₁ = Initial Temperature

T₂ = Final Temperature

Q₁ = Heat available initially

Q₂ = Heat after reaching the temperature T₂

Given:

η =0.280

T₁ = 3.50×10² °C = 350°C = 350+273 = 623K

Q₁ = 3.78 × 10³ J

Substituting the values in the equation (1) we get

$0.28=1-\frac{Q_2}{3.78\times 10^{3}}$

$\frac{Q_2}{3.78\times 10^3}=0.72$

$Q_2=3.78\times 10^3\times0.72$

⇒ $Q_2 =2.721\times 10^3 J$

Now,

The entropy change ( $\Delta S$ ) is given as:

$\Delta S=\frac{\Delta Q}{T_1}$

$\Delta S=\frac{Q_1-Q_2}{T_1}$

substituting the values in the above equation we get

$\Delta S=\frac{3.78\times 10^{3}-2.721\times 10^3 J}{623K}$

$\Delta S=1.69J/K$

7 0

3 years ago

How much work is done by the gravitational force when a 265-kg pile driver falls 2.80m?​

How much work is done by the gravitational force when a 265-kg pile driver falls 2.80m?