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tino4ka555 [31]
3 years ago
8

What is the electron configurations of the gallium ion

Chemistry
1 answer:
yarga [219]3 years ago
7 0

Answer:

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

Explanation:

Gallium is present in group 13.

It has 3 valance electrons.

Electronic configuration:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p¹

There are two possibilities of gallium to form cation.

By removing one 4p electron to form Ga +1 cation.

By removing two 4s electrons and one 4p to form Ga +3 cation.

Gallium is preset in group thirteen that's why common oxidation state is +3.

Electronic configuration of Ga⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁰

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

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How many moles are in 20 grams of O₂ gas?
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When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

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4 0
3 years ago
2. Calculate the mass of 3.47x1023 gold atoms.
lapo4ka [179]

3.47 x 10^{23} atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x 10^{23}

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X 10^{23}

from the relation,

1 mole of element contains 6.022 x 10^{23} atoms.

so no of moles of gold given = \frac{3.47 X 10^{23}  }{6.022 X 10^{23} }

0.57 moles of gold.

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rearranging the equation,

mass = number of moles x atomic mass

mass = 0.57 x 196.96

mass = 113.44 grams

thus, 3.47 x 10^{23} atoms of gold have mass of 113.44 grams

3 0
3 years ago
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