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3 years ago

What is the electron configurations of the gallium ion

Chemistry

1 answer:

yarga [219]3 years ago

7 0

Answer:

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

Explanation:

Gallium is present in group 13.

It has 3 valance electrons.

Electronic configuration:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p¹

There are two possibilities of gallium to form cation.

By removing one 4p electron to form Ga +1 cation.

By removing two 4s electrons and one 4p to form Ga +3 cation.

Gallium is preset in group thirteen that's why common oxidation state is +3.

Electronic configuration of Ga⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁰

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

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igomit [66]

Answer:

$\Delta _RH=4x10^{-3}\frac{kJ}{mol}$

Explanation:

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In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

$\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}$

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

$\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}$

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