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3 years ago

What is the precent yield if the actual yield is 25g and 100g should have formed?

Chemistry

1 answer:

11Alexandr11 [23.1K]3 years ago

3 0

Answer:

Percent yield is 25%

Explanation:

Information given is

Actual yield is 25 g

But the yield should be 100 g

The percent yield is defined as the ratio of the actual yield and the predicted yield it means that out of the predicted yield what percentage of the actual yield is obtained

∴ Percent yield = (Actual yield ÷ Predicted yield) × 100

In case of the given problem the percent yield will be

(25÷100) × 100 = 25%

∴ Percent yield = 25%

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The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

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When the particles of a gas decrease in energy what happens?

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Identifying importance of carbon

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2 years ago

Name the following ester molecule:OA. ethyl butanoateB. propyl pentanoateC. methyl heptanoateD. methylpropanoate

disa [49]

Answer

A. ethyl butanoate

Explanation:

Esters are known for their distinctive odors and are commonly used for food aroma and fragrances. The general formula of an ester is RCOOR'.

Esters are formed through reactions between an acid and an alcohol with the elimination of water.

Esters are named as if the alkyl chain from the alcohol is a substituent. No number is assigned to this alkyl chain. This is followed by the name of the parent chain from the carboxylic acid part of the ester with an –e remove and replaced with the ending –oate.

Hence, the name of the given ester is:

A. ethyl butanoate

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Answer:

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