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pashok25 [27]
3 years ago
9

Calculate thr number of photons having a wavelength of 10.0 μm required to produce 1.0 kJ of energy.

Chemistry
2 answers:
slega [8]3 years ago
7 0

Answer:

The number of photons are 5.028\times 10^{27}.

Explanation:

E=\frac{h\times c}{\lambda}

where,

E = energy of photon =  

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 10.0 μm  =10^{-5} m

1 μm = 10^{-6} m

E=\frac{6.63\times 10^{-34}Js\times 3\times 10^8m/s}{10^{-5} m}

E=1.989\times 10^{-20} Joules

Let the n number of photons with energy equal to E' = 1.0 kJ = 1000 J

n\times E=E'

n\times 1.989\times 10^{-20} J=1000 J

n=\frac{1000 J}{1.989\times 10^{-20} J}=5.028\times 10^{27}

The number of photons are 5.028\times 10^{27}.

ddd [48]3 years ago
4 0
Ok so first you need to figure out the energy of ONE photon with that wavelength. Using E=hc/lambda, you get E= 1.99 * 10^-20 J/photon. Now, how many photons do you need to add up to get to one kilojoule=1000 joules? 1000J / (1.99 * 10^-20 J/photon) = approximately 5 * 10^22 photons hope this helps
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