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3 years ago

How can you express the concentration of hydrogen and hydronium ions in a solution?

Chemistry

1 answer:

Gre4nikov [31]3 years ago

7 0

Answer:

The pH scale is used to express the concentrations of hydronium ions and potassium ions in solutions.

Explanation:

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Rewrite this measurement with a simpler unit, if possible. 8.3 kg•m^2/ s^2

Feliz [49]

Answer: 8.3 J

Explanation:

We have the following measurement:

$8.3 \frac{kg m^{2}}{s^{2}}$

Rearranging the units:

$8.3 \frac{kg m}{s^{2}}m$

Since 1 Newton is $1 N=1 \frac{kg m}{s^{2}}$ :

$8.3 Nm$

Since 1 Joule is $1 J=1 Nm$ :

$8.3 J$ This is the simplest form possible

7 0

2 years ago

The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one

marishachu [46]

Answer:

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere = +3.0 μC = $3\times 10^{-6} C$

$1 \mu C=10^{-6} C$

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q= -3.0 μC = $-3\times 10^{-6} C$

Number of electrons = n

Charge on a single electron, e = $-1.602\times 10^{-19} C$

Q = n × e

$-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)$

$n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}$

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.

4 0

3 years ago

A car moves down the street at 45 kph. The driver takes his foot off the gas pedal but does not brake. Which is the correct expl

nexus9112 [7]

Answer: Friction.

Explanation: Even though the driver has taken the foot off thr gas pedal, the acceleration of the car decreases and the friction continues.

The car slows down because the opposite force of friction continues to act and the acceleration in forward direction is continuous decreasing. Hence, the car slows down.

7 0

3 years ago

Dissolution of KOH, ΔHsoln:

swat32

Using Hess's law we found:

1) By adding reaction 10.2 with the reverse of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) ΔH (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy (ΔH).

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq) ΔHsoln (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq) ΔHneut (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from differents changes in various reactions can be calculated as the sum of all the enthalpies of all those reactions.

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

We need to add reaction 10.2 to the reverse of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

Canceling the KOH(s) from both sides, we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

2) The change in enthalpy for reaction 10.3 can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

$\Delta H = \Delta H_{soln} + \Delta H_{neut}$