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3 years ago

List three applications of pressure in our daily lives.

Physics

2 answers:

Bess [88]3 years ago

6 0

Answer:

1) Skis have a large area to reduce the pressure on the snow. This ensures that the skis do not sink into the snow too far.

2) The pressure under the studs on the soles of football shoes is high enough for them to sink into the ground, which gives extra grip.

3) A vacuum cleaner has a fan inside that creates a low pressure inside the device. Consequently, air and dirt particles are sucked into the device.

aev [14]3 years ago

5 0

Answer:

1 The area of the edge of a knife's blade is extremely small. ...

2 Syringes are used to take blood for blood tests. ...

3 When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.

Explanation:

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A motorcycle is traveling along a highway at 26 m/s. How far does the motorcycle travel in 15 s?

leva [86]

26 m/s for fifteen seconds. distance = rate times time, so distance = 26 m/s * 15 seconds. this gives you distance = 390 meters.

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2 years ago

Introduced species often thrive and multiply in an environment very different from their original one. Why are they often able t

Anestetic [448]

They begin to adapt into their new location. They then end up having adaptations to help them survive.

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2 years ago

In si units, the electric field in an electromagnetic wave is described by ey = 104 sin(1.40 107x − ωt). (a) find the amplitude

melamori03 [73]

Answers:
(a) $B_o = 0.3466$ μT
(b) $\lambda = 0.4488$ μm
(c) f = $6.68 * 10^{14}Hz$

Explanation:
Given electric field(in y direction) equation:
$E_y = 104sin(1.40 * 10^7 x -\omega t)$

(a) The amplitude of electric field is $E_o = 104$ . Hence

The amplitude of magnetic field oscillations is $B_o = \frac{E_o}{c}$
Where c = speed of light

Therefore,
$B_o = \frac{104}{3*10^8} = 0.3466$ μT (Where T is in seconds--signifies the oscillations)

(b) To find the wavelength use:
$\frac{2 \pi }{\lambda} = 1.40 * 10^7$
$\lambda = \frac{2 \pi}{1.40} * 10^{-7}$
$\lambda = 0.4488$ μm

(c) Since c = fλ
=> f = c/λ

Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f = $6.68 * 10^{14}Hz$

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2 years ago

How are CD's recorded?<br> Using digital technology<br> using analog technology

alex41 [277]

I think analog but I could be wrong

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2 years ago

Read 2 more answers

A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially

Alchen [17]

The new speed of car is 10.9 m/s

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According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

$m_1u_1 + m_2u_2 = (m_1 + m_2) v$