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Natali [406]
3 years ago
15

Give the major force between ethanol and rubbing alcohol.

Chemistry
1 answer:
insens350 [35]3 years ago
7 0
The major force between ethanol and rubbing alcohol is hydrogen bond. Hydrogen bond are intermolecular force that are weaker than covalent bond but holds atoms together in a molecules. For an hydrogen bond to be formed, a molecule must contain an hydrogen atom that will be bonded to one of the most electronegative element.
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A procedure calls for 0.250 kg of sugar. Your balance is in ounces. What mass in ounces should be weighed out on this balance?
Elena-2011 [213]

Answer:

8.81849

Explanation:

i believe the whole number would be this but usually i round to the second decimal point, i dont know if you could do that in chemistry tho

5 0
3 years ago
WILL MARK BRAINLIEST please
astra-53 [7]

Answer:

C is the only reasonable answer.. but this is 6th grade science and I'm in 7th, so I'm pretty sure I'm right

5 0
3 years ago
The chemical equation shows the production of magnesium chloride.
Norma-Jean [14]

Answer:

1 gram of H2 will be produced from 12 grams of Mg.

Explanation:

According to Stoichiometry, 0.5 moles of Mg are present. 1 mole of Mg produces 1 mole of H2, so 0.5 moles of Mg will produce 0.5 moles of H2. Multiplying molar mass of H2 i.e. 2 gram/mole with 0.5 moles, we can find the mass of H2 in grams which is 1 gram.

3 0
3 years ago
How many atoms of argon occupy 30.0L
Airida [17]
5.18mL i hope this helps i hope this does to!
6 0
3 years ago
An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0
3 years ago
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