Answer:
0.42%
Explanation:
<em>∵ pH = - log[H⁺].</em>
2.72 = - log[H⁺]
∴ [H⁺] = 1.905 x 10⁻³.
<em>∵ [H⁺] = √Ka.C</em>
∴ [H⁺]² = Ka.C
∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.
<em>∵ Ka = α²C.</em>
Where, α is the degree of dissociation.
<em>∴ α = √(Ka/C) </em>= √(8.065 x 10⁻⁶/0.45) = <em>4.234 x 10⁻³.</em>
<em>∴ percentage ionization of the acid = α x 100</em> = (4.233 x 10⁻³)(100) = <em>0.4233% ≅ 0.42%.</em>
Can you reword it im confused
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or
<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.
For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.
The other three sets are valid and can correctly describe an electron.
