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3 years ago

15

Why is a chemical equilibrium described as dynamic?

1 answer:

Mariulka [41]3 years ago

8 0

Answer:

Chemical equilibrium is also called as dynamic equilibrium because it in chemical equilibrium, the equilibrium can shift towards both sides that is reactant and product known as equilibrium shifting. And in chemical equilibrium, the reaction is going on but the rate of formation of reaction is equals to the rate of formation of product.

Hope this helps!

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When an ionic compound is named or its formula is written, what sort of element is placed first? What is the charge on its ions?

gizmo_the_mogwai [7]

Positive unless your mean to them then everyones negative towards you.

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3 years ago

What is the madd in grams of 0.40 moles of sodium borohydride, NaBH4

Orlov [11]

Answer:

Mass = 15.1 g

Explanation:

Given data:

Number of moles of NaBH₄ = 0.40 mol

Mass in gram = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of NaBH₄ = 37.83 g/mol

By putting values,

Mass = 0.40 mol × 37.83 g/mol

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3 years ago

When acetic anhydride is dissolved in water, it forms acetic acid according to the balanced chemical reaction shown below. calcu

melisa1 [442]

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3 years ago

If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

moles of $NaOH$ = $\frac{57.4\times 1000g}{40g/mol}=1435moles$

moles of $HF$ = $\frac{57.4\times 1000g}{20g/mol}=2870moles$

As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

Mass of cryolite $(Na_3AlF_6)$ = $moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg$

Thus 69.72 kg of cryolite will be produced.

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3 years ago

Rina8888 [55]

B mass but not of charge

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3 years ago