Answer:
A. ΔS°rxn decreases
B. ΔS°rxn decreases
C. ΔS°rxn has little or no change
D. ΔS°rxn increases
Explanation:
The change in entropy (ΔS°rxn) is related to the change in the number of moles of gases (Δn(gas) = n(gas products) - n(gas reactants)). If the number of moles of gases increases, there are more possible microstates and entropy increases. The opposite happens when there are less gaseous moles. And little or no change in entropy is expected when the number of moles of reactants and products is the same.
<em>A. K(s) + O₂(g) ⟶ KO₂(s)</em>
Δn(gas) = 0 - 1 = -1
ΔS°rxn decreases
<em>B. CO(g)+ 3 H₂(g) ⟶ CH₄(g) + H₂O(g)</em>
Δn(gas) = 2 - 4 = -2
ΔS°rxn decreases
<em>C. CH₄(g) + 2 O₂(g) ⟶ CO₂(g)+ 2 H₂O(g)</em>
Δn(gas) = 3 - 3 = 0
ΔS°rxn has little or no change
D. N₂O₄(g) ⟶ 2 NO(g) + O₂(g)
Δn(gas) = 3 - 1 = 2
ΔS°rxn increases
A C and D are all correct, Helium and Hydrogen only have a 1s orbital, and helium has 2 protons, while hydrogen has 1, and finally Hydrogen has no neutrons while helium has 2. Helium does not however have 8 valence electrons as the 1s orbital can only hold 2, meaning B is the “correct” (false) answer.
Answer:
5.6 L
Explanation:
We can apply Charles' Law here since our pressure is constant (will not change inside the refrigerator) and we are relating change in volume with change in temperature:
V₁ / T₁ = V₂ / T₂ where V₁ and T₁ are initial volume and temperature, and V₂ and T₂ are final volume and temperature. Let's plug in what we know and solve for the unknown:
28.0 L / 25 °C = V₂ / 5 °C => V₂ = 5.6 L
5.6 L is our new volume (at 5 °C).
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