Answer:
1. 2.510kJ
2. Q = 1.5 kJ
Explanation:
Hello there!
In this case, according to the given information for this calorimetry problem, we can proceed as follows:
1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:
![1cal=4.184J\\\\1kJ=1000J](https://tex.z-dn.net/?f=1cal%3D4.184J%5C%5C%5C%5C1kJ%3D1000J)
Then, we perform the conversion as follows:
![600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ](https://tex.z-dn.net/?f=600.0cal%2A%5Cfrac%7B4.184J%7D%7B1cal%7D%2A%5Cfrac%7B1kJ%7D%7B1000J%7D%3D2.510kJ)
2. Here, we use the general heat equation:
![Q=mC(T_2-T_1)](https://tex.z-dn.net/?f=Q%3DmC%28T_2-T_1%29)
And we plug in the given mass, specific heat and initial and final temperature to obtain:
![Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ](https://tex.z-dn.net/?f=Q%3D236g%2A0.24%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%2834.9%5C%C2%B0C-8.5%5C%C2%B0C%29%5C%5C%5C%5CQ%3D1495.3J%2A%5Cfrac%7B1kJ%7D%7B1000J%7D%20%5C%5C%5C%5CQ%3D1.5kJ)
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Which of the protist is the most complex organism ?
A) paramecium
<u>B) amoeba
</u>
C) Euglena
D) Volvox
Answer:
B-Sucrose molecules are too large to conduct electricity in once dissolved in water.
D-Salts, like NaCL, have ionic bonds and are considered to be electrolytes:when dissolved in water, salts dissociate and form ions.
Explanation:
The cell notation is:
![Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)](https://tex.z-dn.net/?f=Mg%28s%29%7CMg%5E%7B%2B2%7D%28aq%29%7C%7CAg%5E%7B%2B%7D%28aq%29%7CAg%28s%29)
here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell
in anodic half cell : oxidation takes place [loss of electrons]
in cathodic half cell: reduction takes place [gain of electrons]
1) this is a galvanic cell
2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode
![E^{0}_{Mg}=-2.38V](https://tex.z-dn.net/?f=E%5E%7B0%7D_%7BMg%7D%3D-2.38V)
![E^{0}_{Ag}=+0.80V](https://tex.z-dn.net/?f=E%5E%7B0%7D_%7BAg%7D%3D%2B0.80V)
Therefore
![E^{0}_{cell}=0.80-(-2.38)=+3.18V](https://tex.z-dn.net/?f=E%5E%7B0%7D_%7Bcell%7D%3D0.80-%28-2.38%29%3D%2B3.18V)
3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative
Δ![G^{0}=-nFE^{0}](https://tex.z-dn.net/?f=G%5E%7B0%7D%3D-nFE%5E%7B0%7D)
As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.