16. Nuclear decay is a random event and
1 answer:
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Answer:
The answer to the question is
The temperature at which the vapor pressure will be 5.00 times higher than it was at 331 K is 353.0797 K.
Explanation:
To solve the question, we make use of the Clausius-Clapeyron equation as follows
Where P₁ = Initial pressure
P₂ = Final pressure
T₁ = Initial temperature = 331 K
T₂ = Final temperature
dvapH = ΔvapH = Heat of vaporization = 70.83 kJ / mol.
R = Universal gas constant = 8.3145. J K⁻¹ mol⁻¹
We are required to find the temperature when P₂ = 5 × P₁
Therefore we have
=
or T₂ =
= 353.0797 K
The vapor pressure be 5.00 times higher than it was at 331 K when the temperature is raised to 353.0797 K.
Answer : The complete question is attached in answer.
The value of K will be = 2 X
Explanation : We can use the formula as;
∆G = -RT ln K
on rearranging we get, K =
Therefore, we get,
∆G/RT = (26.81 kJ/mol ) / (0.008314 kJ/mol-K) X (298K) = 10.82
So, K =
Therefore, K = 2 X
