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Sedaia [141]
4 years ago
11

Is the process of introducing a non blood fluid into the blood​

Physics
1 answer:
vladimir1956 [14]4 years ago
4 0
The lymphatic system
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a car traveling in a highway brakes to a stop without skidding. what happens to its kinetic energy? can that energy be recovered
docker41 [41]

Answer:

A car traveling on a highway takes to stop without skidding. What happens to its kinetic energy? ... The energy goes to parts of the brakes. No, the energy can only be reused if there is a heat pump present

7 0
3 years ago
If someone adds millions of small fish to a lake , how would the number of big fish change?
sattari [20]
The population of big fish would increase because they have more food in that area. Hope this helps
6 0
3 years ago
Read 2 more answers
If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rai
stiks02 [169]

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

A=13*10^6m^2

Volume (V) = A*d = (15*10^6)(0.03) = 3.9*10^5m^3

t = 3hours=10800s

\rho = 1000kg/m^3

From the given data we can calculate the volume of rain for 5 seconds

V' = \frac{V}{t}*\Delta t_{total}

Where,

\Delta t_{total} It is the period of time we want to calculate total rainfall, that is

V' = \frac{3.9*10^5}{10800}*5

V' = 1.805*10^2m^3

Through water density we can now calculate the mass that fell during the 5 seconds:

m' = V'*\rho

m' = 1.805*10^2*1000

m' = 1.805*10^5m^2

Now applying the prevailing equation given we have to

P=m'v

P = (1.805*10^5)(10)

P = 1.805*10^6 Kg.m/s

Therefore the momentum of the rain that falls in five seconds is 1.805*10^6 Kg.m/s

4 0
3 years ago
Directions: Consider a 2-kg
nignag [31]

The definition of mechanical energy allows to find the results for the questions about the energy changes in the movement of the system are:

     1) The midpoint of the path. Em = 784 J

     2) Lowest point of the trajectory Em = 784 J

     3) Acceleration of gravity is: g = 9.8 m/s²

     4) The bowling ball has more kinetic energy as its height decreases.

<h3>Mechanical energy.</h3>

Mechanical energy is the sum of the kinetic energy due to motion and the potential energies of the body. In the case of no friction the energy remains constant at all points, this is one of the most important principles of physics.

          Em = K + U

          Em = ½ m v² + m g h

Where Em is the mechanical energy, K and U the kinetic and potential energy, respectively, m the mass, v the velocity. G the acerleacion of gravity and h the height where the body is.

In this case when the ball is on top of the building of height y = 40 m, all its energy is potential.

           Em = U = m g h

           Em = 2 9.8 40

            Em = 784 J

when the body falls it begins to acquire speed, therefore its kinetic energy increases and the height decreases, therefore its potential energy decreases, but the sum of the two remains constant.

1) Let's calculate the energy at the midpoint of the path.

They indicate that the speed is v= 19.8 m/s and the height is y2 = 20m

         Em = ½ m v² + m g h

         em = ½ 2 19.8 ² + 2 9.8 20

         em = 392 + 392

         Em = 784 J

We see that the kinetic and potential energy have the same value and the mechanical energy maintains its initial value.

2) We calculate the energy at the lowest point of the trajectory.

They indicate that the speed is v= 28 m/s and = height is zero h=0

Let's calculate

          Em = ½ m v² + m g h

          Em = ½ 2 28² + 0

          Em = 784 J

At this point, all energy is kinetic and mechanical energy is conserved.

3) The acceleration of gravity comes from Newton's second law where the force is the universal attraction.

           F = G \frac{Mm}{r^2}

           F= ma

           \G frac{Mm}{R^2}

In the case of a body near thesurfacee of the distance of the radius of the planet and the acceleration is called gravity

            g = a = G \frac{M}{R_e^2 }

            g = \frac{ 6.67 \ 10^{-11} \ 5.98 \ 10^{24}}{6.37 \ 10^6 }

            g = 9.81  m/s²

4) The bowling ball has more kinetic energy as its height decreases, at the point where the height is half the kinetic and potential energy are equal.

In conclusion using the definition of mechanical energy we can find the results for the questions about the energy changes in the movement of the system are:

     1) The midpoint of the path. Em = 784 J

     2) Lowest point of the trajectory Em = 784 J

     3) Acceleration of gravity is: g = 9.8 m/s²

     4) The bowling ball has more kinetic energy as its height decreases.

Learn more about mechanical energy here:  brainly.com/question/24443465

7 0
3 years ago
What is the value of w in the equation<br> 1/2w + 7 = 2w - 2
Agata [3.3K]
\frac{1}{2} w + 7 = 2w - 2

First, replace the numerator with 'w'.
\frac{w}{2} +7=2w-2
Second, multiply both sides by 2.
w + 14 = 4w - 2
Third, subtract 'w' from both sides.
14 = 4w - 4 - w
Fourth, simplify to 3w - 4.
14 = 3w - 4
Fifth, add '4' to both sides.
14+4=3w
Sixth, add 14 + 4.
18 = 3w
Seventh, divide both sides by '3'.
\frac{18}{3} =w
Eighth, since 6 goes into 3 to get 18, simplify the fraction to 6.
6 = w
Ninth, switch the sides.
w = 6

Answer: w = 6

7 0
4 years ago
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