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padilas [110]
3 years ago
9

The prefix ‘kilo-‘ means a thousand. So a kilo-gram is a thousand grams. 1 kilogram = 1,000 grams. How many kilograms is 831 gra

ms? Round your answer to the nearest tenth of a kilogram.
Chemistry
1 answer:
Alja [10]3 years ago
5 0
To find the amount of kilograms, you would divide 831 by 1000. 831/1000= 0.831. Round this to the nearest tenth place and the answer is 0.8 kg.
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in an aerosol spray can with a volume of 456 ml contains is 3.18g of propane gas as a propellant If the can is at 23° C and 50 A
Mekhanik [1.2K]

Answer:    Answer:

21.03L

Explanation:

V1 = 456mL = 0.456L

T1 = 23°C = (23 + 273.15)K = 296.15K

P1 = 50atm

V2 = ?

T2 = 273.15K

P2 = 1.0atm

Note : P2 and T2 are at STP which are 1.0atm and 273.15K

To find V2, we have to use the combined gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (50 × 0.456 × 273.15) / (1.0 × 296.15)

V2 = 6227.82 / 296.15

V2 = 21.029L

Final volume of the gas is 21.03L

Explanation:

8 0
3 years ago
An aqueous solution of calcium hydroxide is standardized by titration with a 0.120 M solution of hydrobromic acid. If 16.5 mL of
Artist 52 [7]

<u>Answer:</u> The molarity of calcium hydroxide in the solution is 0.1 M

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HBr

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.120M\\V_1=27.5mL\\n_2=2\\M_2=?M\\V_2=16.5mL

Putting values in above equation, we get:

1\times 0.120\times 27.5=2\times M_2\times 16.5\\\\M_2=0.1M

Hence, the molarity of Ca(OH)_2 in the solution is 0.1 M.

7 0
3 years ago
Help please! I’m in the exam <br> A B C or D
NeX [460]
The answer is d for the answer
6 0
3 years ago
What me with this work sheet plllzz
Brut [27]

Answer:

The answer for 17 is maybe

8 0
3 years ago
Using the following information, what are the values of the exponents in the rate expression, rate = k[A]x[B]y
pashok25 [27]

Answer:

The correct option is;

A) x = 2, y = 1

Explanation:

Here we have

k[0.05]^x \cdot [0.05]^y = 0.062 \ M/sec....................(1)

k[0.05]^x \cdot [0.10]^y = 0.123 \ M/sec....................(2)

k[0.100]^x \cdot [0.100]^y = 0.491 \ M/sec  ..............(3)

From experiment (1), (2) it is observed that [A] is held constant and [B] is doubled of which the rate is also observed to be doubled, therefore, when you double a reactant which result in the rate being doubled, the order of the reaction with respect to the reactant is order 1, therefore, y = 1.

Similarly between reaction (2) and (3) when the concentration of the reactant B is doubled and A is held constant the rate of the reaction is multiplied by a factor of 4, therefore, the reaction with respect to that reactant is order 2, therefore, x = 2.

Therefore, the correct option is x = 2, y = 1.

3 0
3 years ago
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