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padilas [110]
3 years ago
9

The prefix ‘kilo-‘ means a thousand. So a kilo-gram is a thousand grams. 1 kilogram = 1,000 grams. How many kilograms is 831 gra

ms? Round your answer to the nearest tenth of a kilogram.
Chemistry
1 answer:
Alja [10]3 years ago
5 0
To find the amount of kilograms, you would divide 831 by 1000. 831/1000= 0.831. Round this to the nearest tenth place and the answer is 0.8 kg.
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What is the heat of vaporization of ethanol, given that ethanol has a normal boiling point of 63.5°C and the vapor pressure of e
Serjik [45]

Explanation:

According to Clausius-Claperyon equation,

       ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

The given data is as follows.

         T_{1} = 63.5^{o}C = (63.5 + 273) K

                         = 336.6 K

        T_{2} = 78^{o}C = (78 + 273) K

                         = 351 K

         P_{1} = 1 atm,             P_{2} = ?

Putting the given values into the above equation as follows.    

        ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]

       ln (\frac{1.75 atm}{1 atm}) = \frac{-\text{heat of vaporization}}{8.314 J/mol K} \times [\frac{1}{351 K} - \frac{1}{336.6 K}]

                      \Delta H = \frac{0.559}{1.466 \times 10^{-4}} J/mol

                                  = 0.38131 \times 10^{4} J/mol

                                  = 3813.1 J/mol

Thus, we can conclude that the heat of vaporization of ethanol is 3813.1 J/mol.

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