Answer: Answer:
21.03L
Explanation:
V1 = 456mL = 0.456L
T1 = 23°C = (23 + 273.15)K = 296.15K
P1 = 50atm
V2 = ?
T2 = 273.15K
P2 = 1.0atm
Note : P2 and T2 are at STP which are 1.0atm and 273.15K
To find V2, we have to use the combined gas equation,
(P1 × V1) / T1 = (P2 × V2) / T2
P1 × V1 × T2 = P2 × V2 × T1
V2 = (P1 × V1 × T2) / (P2 × T1)
V2 = (50 × 0.456 × 273.15) / (1.0 × 296.15)
V2 = 6227.82 / 296.15
V2 = 21.029L
Final volume of the gas is 21.03L
Explanation:
<u>Answer:</u> The molarity of calcium hydroxide in the solution is 0.1 M
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is 
We are given:

Putting values in above equation, we get:

Hence, the molarity of
in the solution is 0.1 M.
The answer is d for the answer
Answer:
The answer for 17 is maybe
Answer:
The correct option is;
A) x = 2, y = 1
Explanation:
Here we have
....................(1)
....................(2)
..............(3)
From experiment (1), (2) it is observed that [A] is held constant and [B] is doubled of which the rate is also observed to be doubled, therefore, when you double a reactant which result in the rate being doubled, the order of the reaction with respect to the reactant is order 1, therefore, y = 1.
Similarly between reaction (2) and (3) when the concentration of the reactant B is doubled and A is held constant the rate of the reaction is multiplied by a factor of 4, therefore, the reaction with respect to that reactant is order 2, therefore, x = 2.
Therefore, the correct option is x = 2, y = 1.