Answer:
sp³
Explanation:
Number of hybrid orbitals = ( V + S - C + A ) / 2
Where
H is the number of hybrid orbitals
V is the valence electrons of the central atom = 5
S is the number of single valency atoms = 4
C is the number of cations = 1
A is the number of anions = 0
For PCl₄⁺
Applying the values, we get:
H = ( 5+4-1+0) / 2
= 4
<u>This corresponds to sp³ hybridization.</u>
It should have 10 electrons
First, you need to calculate the standard cell potential using standard reduction potential from a textbook or online. Since Mg becomes Mg+2, magnesium is being oxidized because it is losing electrons, you need to flip its potential
Fe+2 + 2e- --> Fe potential= -0.44
Mg+2 + 2e- --> Mg potential= -2.37
Cell potential= (-0.44) + (+2.37)= 1.93 V
Now, you need to use Nernst formula to get the answer. I have attached a PDF with the work.
The atomic radius increases down a column (group) and decreases along a row
