<h3>
Answer:</h3>
4.227 × 10^-19 Joules
<h3>
Explanation:</h3>
Energy of a photon of light is calculated by the formula;
E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.
But, f = c/λ
Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.
Given the wavelength is 470 nm or 4.7 × 10^-7 m
Therefore;
E = hc/λ
= (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m
= 4.227 × 10^-19 Joules
Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules
Answer:
True;
True;
False;
True;
True.
Explanation:
Organic compounds can be found pure, but generally, they are in mixtures, such as the petroleum, so it is possible to the compound received be impure;
Organic compounds can be found in the three states: solid, liquid or gas. The state will depend on the molecular forces in it and its molar mass. For example, gasoline is liquid in the ambient temperature, natural gas is a gas, and the glucose is solid;
The main characteristic of the organic compounds is the presence of C and H, the other elements can or can't be in the structure: O, N, halogens, and S;
Because of the carbon can form chains, there are several million possible known organic compounds;
The spectroscopic would give some results such as composition, molar mass, and diffraction, and with these results, it would be possible to identify some chemical properties and the tests needs more identification.
