Answer:
If the force applied is larger than 185.2 N, yes.
Explanation:
In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

where
is the coefficient of static friction
is the mass of the table
is the gravitational acceleration
Substituting,

So, we are able to move the table if we push with a force larger than 185.2 N.
the mass number minus the atomic number
Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π ×
................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second
Answer:
887.1Hz
Explanation:
Given parameters:
Speed of sound wave = 330m/s
Wavelength = 0.372m
Unknown:
Frequency = ?
Solution:
To solve this problem, we use the expression below:
Speed = Frequency x wavelength
330 = Frequency x 0.372
Frequency = 887.1Hz
Answer:
the pressure will decrease by 1/2
Explanation:
PV=nRT
P=(nRT)/(V)
nRT are all constant so they will equal 1
V is 2
P=1/2