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Masteriza [31]
3 years ago
10

given the following equation: 8 H2 + S8 −−> 8H2S what is the molar relationship between H2 and H2S

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
4 0
-(1/8)Δ[H2S]/Δt = -(1/4)Δ[O2]/Δt
(1/8)Δ[H2S]/Δt = (1/4)Δ[O2]/Δt
(4)*((1/8)Δ[H2S]/Δt) = (4*)((1/4)Δ[O2]/Δt)
(1/2)Δ[H2S]/Δt = Δ[O2]/Δt
(1/2))*( -0.057 M/s) = Δ[O2]/Δt
Δ[O2]/Δt = -0.0285 M/s
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\large \boxed{\text{4.5 atm}}

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\begin{array}{rcl}\dfrac{5.7}{373.15} & = & \dfrac{p_{2}}{293.15}\\\\0.0153 & = & \dfrac{p_{2}}{293.15}\\\\0.0153\times 293.15 &=&p_{2}\\p_{2} & = & \textbf{4.5 atm}\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.5 atm}}$}

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