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Norma-Jean [14]
2 years ago
15

A green powder was placed into a beaker of water. After it was stirred the water looked cloudy and lumps of powder could still b

e seen. Has a solution been formed? Explain your answer?
Chemistry
1 answer:
sukhopar [10]2 years ago
7 0

Answer:

it make poisionus police come and took away

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Which of these are associated with the solar wind? Check all that apply.
WINSTONCH [101]

Answer:

Disrupts communication systems

Composed of charged particles

travels at about 400 km/s

8 0
3 years ago
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Assuming that the only lons contributing to the salt content in the Dead sea is Nat
marshall27 [118]

Answer:

3.37kg of NaCl is the salt content of the dead sea

Explanation:

A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.

To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:

<em>Volume in milliliters:</em>

10.0L * (1000mL / 1L) = 10000mL

<em>Mass of NaCl:</em>

10000mL * (33.7g NaCl / 100mL) = 3370g NaCl

<em>In kg:</em>

3370g * (1kg / 1000g) =

<h3>3.37kg of NaCl is the salt content of the dead sea</h3>
6 0
3 years ago
Would carbon dioxide or water have a higher boiling point? Explain.
oee [108]

Answer:

Water acutually has a higher boiling point because CO2 will turn into a gas form at a certain temp ( -78 C), so CO2 wouldn't really boil very long.

Hope this helps:)

7 0
4 years ago
What volume of a 0.100MHCl0.100MHCl stock solution should be used to prepare 250.00mL250.00mL of 0.0250MHCl0.0250MHCl?​
vladimir2022 [97]
<h3>Answer:</h3>

62.5 mL

<h3>Explanation:</h3>

<u>We are given;</u>

  • Molarity of the stock solution as 0.100 M
  • Volume of the dilute solution as 250 mL
  • Molarity of dilute solution as 0.0250 M

We are required to calculate the Volume of the stalk solution.

  • Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.

We are going to use the dilution formula;

  • According to the dilution formula, M₁V₁ = M₂V₂
  • Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

    = (0.025 M × 0.25 L) ÷ 0.100 M

    = 0.0625 L

But, 1 L = 1000 mL

V₁ = 62.5 mL

Therefore, the volume of the stock solution is 62.5 mL

6 0
3 years ago
1. Is the equation above balanced or unbalanced? Zn + 2HCl ---&gt; ZnCl2 + H2
ss7ja [257]

Answer:it is balanced

Explanation:

u can see that there is 1 ZN on both side, 2H on both side, 2Cl on both side, so it is balanced

5 0
4 years ago
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