Answer:
1-chloro-1-methylcyclohexane
Explanation:
The hydrocarbons with one double bond are called alkenes and are named with the suffix "ene". The alkenes, such as 1-methylcyclohexene, react better in an addition reaction. The double bond will be broken, and the substitutes will be placed at them.
In the reaction with HCl, H and Cl will be added to the carbons of the broken bond. The major product is formed when H is put at the carbon less substituted. Thus, the product will be the one given below, 1-chloro-1-methylcyclohexane.
Answer:
5 L
Explanation:
We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:
Mole of CaCl₂ = 0.5 mole
Volume = 2 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.5 / 2
Molarity = 0.25 M
Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:
Molarity of stock solution (M₁) = 0.25 M
Volume of stock solution (V₁) = 2 L
Molarity of diluted solution (M₂) = 0.1 M
Volume of diluted solution (V₂) =?
M₁V₁ = M₂V₂
0.25 × 2 = 0.1 × V₂
0.5 = 0.1 × V₂
Divide both side by 0.1
V₂ = 0.5 / 0.1
V₂ = 5 L
Thus the volume of the diluted solution is 5 L
Answer:
22.6666666666666666 and so on
Explanation:
68÷3