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erma4kov [3.2K]
3 years ago
8

What are the characteristics of high energy waves?

Physics
2 answers:
liq [111]3 years ago
6 0

<u><em>Answer:</em></u>

  • <em>High energy waves are louder</em>
  • <em>Have a higher amplitude</em>
  • <em>Peaks are higher and the valleys are lower</em>

<em />

<u><em>Explanation:</em></u>

<em>*Hope this helps*</em>

<u><em /></u>

Temka [501]3 years ago
4 0
Amplitude and frequency
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Does a car have antennae?what senses does it have?
brilliants [131]

Answer:

The ground of an antenna needs to be attached to the car in such a way that the voltage of the antenna can connect to the earth. This connection allows the earth to receive and store excess voltage rather than the extra voltage bouncing back through your antenna and radio.

Explanation:

pls give brainliset

4 0
3 years ago
You stand17.5 m from a wall holding a baseball. You throw the baseball at the wall at an angle of 20.5∘ from the ground with an
Lelechka [254]

Answer: 8.8 m

Explanation:

The movement of the baseball to the wall is a example of parabolic motion. While the baseball aproach the wall it is affected by gravity.

In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:

Vx = Vo * cos(∅)

Vy = Vo * sin(∅)

Where Vo is the initial velocity 27.5 m/s, and ∅ is the angle which is 20.5°. So we calculate:

Vx = 27.5m/s * cos(20.5)

Vx = 27.5m/s * 0.936

Vx = 25.74m/s

Vy = 27.5m/s  * sin(20.5)

Vy = 27.5m/s * sin(20.5)

Vy = 9.62m/s

Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.

To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:

Time (T) = Distance (D) / Velocity (V)

Where Distance is 17.5m and our Velocity is the Vx calculated before.

T = 17.5 m / 25.74m/s

T = 0.68s

This is the time it takes the ball to reach the wall.

Know with the time, we can calculate the how tall it got on that time with the following equation:

x = (Vo*t) + (\frac{1}{2} *a*t^{2} )

Where Vo is the Y-Compound of the Initial Velocity.

a is the aceleration, in this case the Gravity. Which, will be negative because is oposing the movement. Gravity is equal to 9.81 m/s^{2}

And t is the time it takes the ball to get to the wall.

x = (Vy*T) + (\frac{1}{2} *g*T^{2} )

x = ((9.62m/s)*0.68s) + (\frac{1}{2} *(9.81m/s^{2})*(0.68s)^{2} )

x = 8.8 m

This is the height that the baseball touch the wall.

6 0
3 years ago
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.320 m2. at
AlexFokin [52]
Remember, half of the energy in an EM wave is in the E field, the rest is in the B field. Thus, multiply E field energy by 2.
To calculate the energy of the wave you must then use the following equation: W = A*t*c*2*(1/2*E^2*Eo). Where, A = Area, t = time, c = speed of light (which is a constant), E = Electric field, E0 = vacuum permittivity (8.85*10^-12 Nm^2/C^2). Substituting W =(0.320)*(26)*(3*10^8)*(2)*((1/2)*(1.95*10^-2)^2*(8.854*10^-12)) = 8.40*10^-6 J
5 0
3 years ago
2. A boy lifts a 30N toy car 3 meters
GarryVolchara [31]

Answer:

<h2>90 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 30 × 3

We have the final answer as

<h3>90 J</h3>

Hope this helps you

6 0
3 years ago
What is the maximum number of orbitals in the p sublevel?
dedylja [7]

Answer:

3 orbitals

Explanation:

The p sublevel can carry a maximum of 6 electrons. Therefore it must be made of 3 orbitals which each, as in any orbital of any other sublevel, can carry 2 electrons. So there is a p sub x orbital, p sub y orbital and p sub z orbital which are all orthogonal to each other.  

7 0
3 years ago
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