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GREYUIT [131]
2 years ago
15

Four different resistors have various amounts of electric current flowing through them. Given the values of current I and resist

ance R in each case, order the resistors by the voltage across them, from highest to lowest.
Physics
1 answer:
Artemon [7]2 years ago
3 0

You did not provide the options. However, the options are

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0ohms

I = 8.0, R= 8.0 ohms

Answer:

The order of  the resistors from the highest to the lowest is:

I = 8.0, R= 8.0 ohms

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0 ohms

Explanation:

ohm's law states that voltage across a conductor is directly proportional to the current flowing through it.  V = IR

Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest

  • For I = 8.0, R= 8.0 ohms

       V = 8 * 8 =64 volts

  •  For I = 6.0, R= 4.0 ohms

      V = 6 * 4 =24 volts

  • For I = 9.0, R= 2.0 ohms

       V = 9 * 2 =18 volts

  • For I = 3.0, R= 2.0 ohms

       V = 3 * 2 =6 volts

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Harman [31]
Hey user!

your answer is here..

correct option is A. steel

we know that sounds travel faster in solid as compared to gas and liquids. in gas the molecules are very loosely packed and there is lot of space between so it takes more time to pass sound from each other. and in liquid, the molecules are closer as compared to gas hence it will be little faster and in solid, the molecules are very tightly packed so it will be the fastest. and among these options, steel is the only solid so the speed of sound in steel will be the fastest.

and note that the closer the molecules are to each other ( tightly packed ) makes the bond also tighter and less time to pass sound.

cheers!!
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mamaluj [8]
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