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Alex17521 [72]
3 years ago
13

How many significant figures are in the measurement 0.020 km?

Physics
2 answers:
nirvana33 [79]3 years ago
7 0

Answer:

2

Explanation:

0.020 has two significant figures.

The 2 is significant because all non-zero numbers are signficant.

The second 0 is significant because all zeros at the end of a decimal are significant.

The other zeros are not significant, because they are just place holders.

Volgvan3 years ago
4 0

Answer:3

Explanation:

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Gemiola [76]

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Explanation:

3 0
2 years ago
Pls help. This is about heat. I got the answer, just need the working
Mars2501 [29]

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C  from 20 C

  this will take   .20 kg *    390 j /kg-C   *  80 C = <u>6240 j</u>

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take    

    .50 kg * 4182 j/kg-C  * 80 = <u>167,280 j </u>

AND you have to add enough heat to boil off  .03 kg of water:

   .03 kg * (2260000 j/kg-C )  =<u> 67,800 j</u>

<u />

Power = joules / sec =  (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>

<u />

<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>

7 0
2 years ago
We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one
Len [333]

Answer:

A=1

B=-2

Explanation:

Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.

From part B as attached, it shows that the right option is C which is

2A+3B=-4

Substituting B with 3A-5 then we form the second equation as shown

2A+3(3A-5)=-4

By simplifying the above equation, we obtain

2A+9A-15=-4

Re-arranging, then

11A=-4+15

Finally

11A=11

A=1

To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain

B=3(1)-5=-2

Therefore, required values are 1 and -2

3 0
3 years ago
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DENIUS [597]

Answer:

50 N

Explanation:

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2 years ago
Calculate the mass of an 86kg object on the moon
Vikentia [17]
If an object that is 86kg on the moon then that is the answer, 86kg.
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2 years ago
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