Answer:
if you look it up i think u can find it it could be a mealltiod Co 27
Explanation:
Answer:
See below
Explanation:
You have to heat the calorimeter to 100 C from 20 C
this will take .20 kg * 390 j /kg-C * 80 C = <u>6240 j</u>
You have to heat the mass of water to boiling point (100 C ) from 20C
this will take
.50 kg * 4182 j/kg-C * 80 = <u>167,280 j </u>
AND you have to add enough heat to boil off .03 kg of water:
.03 kg * (2260000 j/kg-C ) =<u> 67,800 j</u>
<u />
Power = joules / sec = (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>
<u />
<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>
Answer:
A=1
B=-2
Explanation:
Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.
From part B as attached, it shows that the right option is C which is
2A+3B=-4
Substituting B with 3A-5 then we form the second equation as shown
2A+3(3A-5)=-4
By simplifying the above equation, we obtain
2A+9A-15=-4
Re-arranging, then
11A=-4+15
Finally
11A=11
A=1
To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain
B=3(1)-5=-2
Therefore, required values are 1 and -2
If an object that is 86kg on the moon then that is the answer, 86kg.