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sergejj [24]
3 years ago
5

Lonization energy is the

Chemistry
1 answer:
Tamiku [17]3 years ago
3 0
Arrow on the table below draw an
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In which era did the first fish appear?
VARVARA [1.3K]
C Because Mesozoic Is An Era The First Fish Seen
5 0
4 years ago
The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
If there is currently 50kg of U-235 present in Oklo, how much must have been present 750 million years ago when the reaction too
Viefleur [7K]
To answer this question, you need to know the concept of half-life, which is how a radioactive material decreases in mass over time.

The half life of U-235 is 703.8 million years. The first part of this problem is to find the scale factor. To do this, divide the time that has past by the half life, like this:

\frac{750}{703.8}  = 1.066
Now, take this scale factor and multiply it by the current mass, like this:

50 \times 1.066 = 53.3
This number is what you add to the current mass to get the original mass. That is because the scale factor showed us that it was just over one half life. Since after one half life, the mass is cut in half, and this is over one half life, when we add to the original it will be a little over double. This equation illustrates the final addition:

50 + 53.3 = 103.3
I hope this helped you. Fell free to ask any further questions.
7 0
3 years ago
Where do an organisms genes come from?
andriy [413]

Answer:

Organisms genes come from both mother and father :3

Explanation:

:3

3 0
3 years ago
4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in kPa?
Semenov [28]
Assuming that nitrogen gas is ideal, we can use the equation PV = nRT to relate first conditions to the second condition. At constant temperature, pressure and volume are indirectly related as follows:

P = k / V

k is equal nRT

P1V1 = P2V2
P2 = 101.325 ( 4.65 ) / .480 = 981.586 kPa
6 0
3 years ago
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