A worm, a squid, an octopus, and a beetle are all

There are eight diastereomers of 1,2,3,4,5,6-hexachlorocyclohexane. One of them is drawn. Draw the other seven in the cyclohexan

Marianna [84]

Answer:

Attached below diagram of the eight diastereomers

The Isomer that reacts so slowly is DIASTEREOMER 8

Explanation:

The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination

attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )

3 0

3 years ago

Could someone describe a procedure to separate a mixture of salt, sand, and water?

frosja888 [35]

Water and salt, since the salt has dissolved into the water, assumingly, and sand isn't dissolvable so it can't pass through. If the water were to dry up, then you'd get the salt back, then it won't be able to go through the filter

4 0

3 years ago

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Which layer of the sun is responsible for producing the light shown in the picture above? Radiative zone Convective zone Photosp

victus00 [196]

Answer:

Answer Expert Verified

The lights shown in the figure comes from the outermost layer of the Sun. This layer is called photosphere. This is the layer from where the light of the Sun is radiated, before travelling through space and reaching us.

4 0

3 years ago

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Write a report on the implications of entropy to a Christian 500 words

Neko [114]

The universe is "running down," becoming randomly scattered and disorganized, tending to break down into its simple parts. Metals rust, parts wear out, dead organisms decay and turn to dust. The entropy of the universe is increasing.

The Bible provides an answer. A great amount of energy had to be expended to produce such great organization. As one scientist states the problem, energy was not enough. If you are asked to "reduce the entropy" of your room (put it in order), you certainly need to put in some effort (energy). But just adding energy is not enough. You could let loose a bull in your room, and it would expend a great deal of energy; however, that energy would not decrease but would increase the disorder of the room. Therefore, scientists know that to produce order, energy must be intelligently directed. Evolution requires that atoms and molecules assemble themselves into increasing order, but the science of thermodynamics assures us that the entire universe, when left to itself, is converting to disorder. The Apostle Paul referred to this concept when he said through inspiration that the entire earth is "subject to the bondage of decay." The original state required an intelligence to organize the complexities of the universe.

Christians, of course, have an answer to these perplexing questions: God. God is the Creator of the universe, the ultimate source of its energy and order. He created it with no entropy (no disorder). When man sinned, the universe began to increase in entropy (become more and more disordered). For Christians a discussion of energy, thermodynamics, and entropy is inspiring. These subjects invariably point us to the One who created the universe and sustains it by His power. Christians also know that His power will one day totally renew the universe and entropy will have no part in it.

Christians need never be afraid of science. God is in control of the universe and all the laws of the universe operate according to His will and design. Christians should be confident that they have the answers to the perplexing questions of nature.

Part 2

The above attitude allows christians to ignore questions that are difficult and this leads to mental complacency.

"This is gods work. I must not question or touch this". Is their motto.

When christians see difficult questions, such as entropy and creation, that is where they stop thinking and attribute it to god. They become intellectually crippled and refuse to make that one further step. It then halts progress until the shamen can integrate new knowledge into their mantra and dogma.

Science in general, tries to explain and understand and make further progress and additions to human knowledge. Christians will only try to understand what they have been taught and integrate any new knowledge when the older beliefs become untenable.

3 0

3 years ago

You are provided with 300.0 mL of a buffer solution consisting of 0.200 M H3BO3 and 0.250 M NaH2BO3.

My name is Ann [436]

Answer:

a. 9.34

b. 9.06

c. 6 mL

Explanation:

Part a.

The pH of a buffer solution is given by the Henderson-Hasselbach equation:

pH = pKa + log [A⁻] / [HA]

where pKa is the negative log of Ka for the weak acid H₃BO₃ and can be obtained from reference tables, [A⁻] and [HA] are the concentrations of the weak conjugate base H₂BO₃⁻ and and the weak acid H₃BO₃ respectively.

Proceeding with the calculations, we have

Ka H₃BO₃ = 5.80 x 10⁻¹⁰

pKa = - log (5.80 x 10⁻¹⁰) = 9.24

[H₂BO₃⁻ ] = 0.250 M

[H₃BO₃] = 0.200 M

pH = 9.24 + log (0.250/0.200) = 9.34

part b.

When 1.0 mL of 6.0 M HCl is added to the buffer , we know that it will react with the conjugate base in the buffer doing what buffers do: keeping the pH within a small range according to the capacity of the buffer:

H₂BO₃⁻ + H⁺ ⇒ H₃BO₃

So lets calculate the new concentrations of acid and conjugate base after reaction and apply the Henderson equation again:

Initial # of moles:

H₃BO₃ = 0.300 L x 0.200 mol/L = 0.06 mol

H₂BO₃⁻ = 0.200 L x 0.250 mol/L = 0.05 mol

mol HCl = 0.001 L x 6.0 mol/L = 0.006 mol

After reaction

H₃BO₃ = 0.06 mol + 0.006 mol = 0.066 mol

H₂BO₃⁻ = 0.05 mol - 0.006 mol = 0.044 mol

New pH

pH = 9.24 + log ( 0.044 / 0.66 ) = 9.06

Note: There is no need to calculate the new concentrations since we have a quotient in the expression where the volumes cancel each other.

Part c.

We will be using the Henderson-Hasselbach equationm again but now to calculate ratio [H₂BO₃⁻] / [HBO₃] that will give us a pH of 10.00. Thenwe will make use of the stoichiometry of the reaction to calculate the volume of NaOH required.

pH = pKa + log[H₂BO₃⁻]-[H₃BO₃]

10.00 = 9.24 + log [H₂BO₃⁻]-[H₃BO₃]

⇒[H₂BO₃⁻] / [H₃BO₃] = antilog (0.76) = 5.75

Initiall # moles:

mol H₃BO₃ = 0.06 mol

mol H₂BO₃ = 0.05 mol

after consumption of H₃BO₃ from the reaction with NaOH:

H₃BO₃ + NaOH ⇒ Na⁺ + H₂BO₃⁻ + H₂O

mol H₃BO₃ = 0.06 - x

mol H₂BO₃⁻ = 0.05+ x mol

Therefore we have the algebraic expression:

[H₂BO₃⁻] / [H₃BO₃] = mol H₂BO₃⁻ / mol HBO₃ = 5.75

( again volumes cancel each other)

0.05 + x / 0.06 - x = 5.75 ⇒ x = 0.044

SO 0.037 mol NaOH were required, and since we know Molarity = mol / V we can calculate the volume of 6.0 M NaOH added:

V = 0.044 mol / 6.0 mol/L = 0.0073 L

V = 7.3 mL

6 0

4 years ago