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AveGali [126]
3 years ago
9

If photosynthesizing green algae are provided with CO2 containing heavy oxygen (18O), subsequent analysis will show that 18O is

absent from which of the following molecules produced by the algae?
A) 02
B) glyceraldehyde 3-phosphate (G3P)
C) glucose
D) ribulose bisphosphate (RuBP)
Chemistry
1 answer:
pogonyaev3 years ago
8 0

Answer: A. O2

Explanation:

If photosynthesizing green algae are provided with CO2 containing heavy oxygen (18O), subsequent analysis will show that 18O first appears then 3-phosphoglycerate molecule produced by the algae.

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When n=2 we have 8electrons, when n=4 l=1 we have 6electrons, when n=6 l=2 m-l=-1 qe have 1electron
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What is √200 in simplest form?​
GREYUIT [131]

Answer:

14.14

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4 years ago
A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i
ElenaW [278]

Answer:

470 °C  

Explanation:

This looks like a case where we can use Charles’ Law:  

\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}

Data:

V₁ = 20 L; T₁ = 100 °C

V₂ = 40 L; T₂ = ?  

Calculations:

(a) Convert the temperature to kelvins

T₁ = (100 + 273.15) K = 373.15 K

(b) Calculate the new temperature

\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

T₂ = (750 – 273.15) °C = 470 °C

3 0
3 years ago
If a sample of sodium chloride with a mass of
alex41 [277]
Original molarity was 1.7 moles of NaCl

Final molarity was 0.36 moles of NaCl

Given Information:

Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity

Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity

1. Solve for the molarity of the original (concentrated) solution.

Molarity (M) = moles of solute (mol) / liters of solution (L)

Convert the given information to the appropriate units before plugging in and solving for molarity.

Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)

2. Solve for the molarity of the final (diluted) solution.

Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.

Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution

Molarity (M) of the final solution = 0.36 M NaCl

I hope this helped:))
6 0
3 years ago
Drag the labels onto the table to indicate when each statement Is true. Labels can be used once, more than once, or not at all.
liq [111]

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In chemistry, attention is the abundance of a constituent divided by way of the total quantity of an aggregate. several types of mathematical descriptions may be prominent: mass concentration, molar concentration, range concentration, and quantity concentration.

it's miles the amount of solute dissolves in one hundred g solvent. If the attention of the answer is 20 %, we understand that there are 20 g solutes in one hundred g solution. instance: 10 g salt and 70 g water are mixed and the solution is ready. find awareness of the answer by means of percentage mass.

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brainly.com/question/26255204

#SPJ4

3 0
1 year ago
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