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AveGali [126]
3 years ago
9

If photosynthesizing green algae are provided with CO2 containing heavy oxygen (18O), subsequent analysis will show that 18O is

absent from which of the following molecules produced by the algae?
A) 02
B) glyceraldehyde 3-phosphate (G3P)
C) glucose
D) ribulose bisphosphate (RuBP)
Chemistry
1 answer:
pogonyaev3 years ago
8 0

Answer: A. O2

Explanation:

If photosynthesizing green algae are provided with CO2 containing heavy oxygen (18O), subsequent analysis will show that 18O first appears then 3-phosphoglycerate molecule produced by the algae.

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Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents
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Answer:

Explanation:

a) Mg + NiCl_2 \rightarrow MgCl_2 + Ni

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and NiCl_2 acts as oxidizing agent.

b) PCl_3 + Cl_2 \rightarrow PCl_5

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

PCl_3 acts as reducing agent and Cl_2 acts as oxidizing agent.

c) C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

C_2H_4 acts as reducing agent and O_2 acts as oxidizing agent.

d) Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and H_2SO_4 acts as oxidizing agent

e) K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

K_2S_2O_3 acts as reducing agent and I_2 acts as oxidizing agent.

f) 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and HNO_3 acts as oxidizing agent

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