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Elena L [17]
3 years ago
15

Before you go.. Is there something I could've said to make your heart beat better?

Physics
2 answers:
Zinaida [17]3 years ago
7 0

Answer:

no ... hahahha! but I know every boys wait for the day when their heart beat is faster than normal ever in life

den301095 [7]3 years ago
6 0
Free points ! That makes me happy
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What would be the effect of adding a proton to a nucleus?
Lisa [10]

Answer:

A

Explanation:

The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.

7 0
2 years ago
A soccer ball with a mass of 0.434 kg approaches a player horizontally with a speed of 13.0 m/s. The player kicks the ball with
zaharov [31]

Answer:

a) 15.49

b) Opposite to the ball's initial velocity

c) 258.16N

Explanation:

a)

\Delta p=m \Delta v\\\\\Delta p= (0.434)(13.0-(-22.7)) \\\\\Delta p=(0.434)(35.7)\approx 15.49 kg \cdot m/s

b)

Since the player is kicking the ball in the opposite direction to which it came, the impulse is being directed opposite to the ball's initial velocity.

c)

\Delta p= F \Delta t \\\\\\F=\dfrac{\Delta p}{\Delta t} \\\\\\F=\dfrac{15.49 kg \cdot m/s}{0.06 s}\approx 258.16N

Hope this helps!

7 0
4 years ago
Why type of volcano is built almost entirely from ejected lava fragments
GaryK [48]

Answer:

Shield volcanoes

Explanation:

5 0
3 years ago
A tank whose bottom is a mirror is filled with water to a depth of 19.6 cm. A small fish floats motionless a distance of 6.40 cm
ANEK [815]

Answer:

A. 4.82 cm

B. 24.66 cm

Explanation:

The depth of water = 19.6 cm

Distance of fish  = 6.40 cm

Index of refraction of water = 1.33

(A). Now use the below formula to compute the apparent depth.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\= \frac{1}{1.33} \times 6.40 \\= 4.82 cm.

(B). the depth of the fish in the mirror.

d_{real} = 19.6 cm + (19.6 cm – 6.40 cm) = 32.8 cm

Now find the depth of reflection of the fish in the bottom of the tank.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\d_{app} = \frac{1}{1.33} \times 32.8  = 24.66\\

4 0
3 years ago
Write about Geothermal energy????????????
svlad2 [7]
Energy Produced by water and heatfrom the inner core of the earth of the earth
8 0
3 years ago
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