Answer:
mass of the second ball is 0.379m
Explanation:
Given;
mass of first ball = m
let initial velocity of first ball = u₁
let final velocity of first ball = v₁ = 0.45u₁
let the mass of the second ball = m₂
initial velocity of the second ball, u₂ = 0
let the final velocity of the second ball = v₂
Apply the principle of conservation of linear momentum;
mu₁ + m₂u₂ = mv₁ + m₂v₂
mu₁ + 0 = 0.45u₁m + m₂v₂
mu₁ = 0.45u₁m + m₂v₂ -------- equation (i)
Velocity for elastic collision in one dimension;
u₁ + v₁ = u₂ + v₂
u₁ + 0.45u₁ = 0 + v₂
1.45u₁ = v₂ (final velocity of the second ball)
Substitute in v₂ into equation (i)
mu₁ = 0.45u₁m + m₂(1.45u₁)
mu₁ = 0.45u₁m + 1.45m₂u₁
mu₁ - 0.45u₁m = 1.45m₂u₁
0.55mu₁ = 1.45m₂u₁
divide both sides by u₁
0.55m = 1.45m₂
m₂ = 0.55m / 1.45
m₂ = 0.379m
Therefore, mass of the second ball is 0.379m (where m is mass of the first ball)
The 100 mL because it has less space to fill up with the tenperature
Answer:
The correct wording is
- Pressure increases with the depth of the fluid.
- A plane's engines produce thrust to push the plane forward.
- A fluid can be a liquid or a gas.
- A hydraulic device uses Pascal's principle to lift or move objects.
- lift is the upward force exerted on objects by fluids.
Explanation:
1. As you go deeper into a fluid,<em> there is more of it on top of you; </em>therefore, the pressure excreted on you is greater.
2. A plane's engines pushes the air in opposite direction, which according to newton's third law, produces necessary force to move the plane forward.
3. <em>A fluid has no fixed shape,</em> and it deforms under the influence of external forces applied—liquid and gases fit into this definition.
4. Pascal's principle <em>says that pressure applied on one region of the fluid must equal pressure transmitted to another region of the same fluid</em>. This principle is used in a hydraulic device to exert forces on fluids to lift objects that would otherwise be difficult to move.
5. By definition, the upward force exerted by the fluids on objects is the lift.
This should help
there always needs to be the two electrons first if possible the 8 electrons for each shell till the number of electron runout
