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sveta [45]
3 years ago
11

A force Ě = F, î + Fy h acts on a particle

Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

Pt 1: W=39J

Pt 2: θ = 19.7

Explanation:

Part 1:

W=FS

W=F_{_xs_x}+F{_ys_y}

imagine the "i"and the "j" with the hat

W=(10i-1j)(4i+3j)

W=(10*4)-(1*1)

W=40-1

W=39J

Part 2:

|F|=\sqrt{10^2+(-1)^2}

|F|=\sqrt{101}

|S|=\sqrt{4^2+1^2}

|S|=\sqrt{17}

W=|F||S|cosθ

39=(\sqrt{101})(\sqrt{17} )cosθ

θ = 19.7

Hope it helps

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Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is
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The car B has the velocity of 25 Km/hr.

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[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

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As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are v'_{1} \ and\ v'_{2}

Hence the final momentum of the system is-

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Answer:

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Answer:

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