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3 years ago

A force Ě = F, î + Fy h acts on a particle

Physics

1 answer:

AVprozaik [17]3 years ago

8 0

Answer:

Pt 1: $W=39J$

Pt 2: θ = $19.7$

Explanation:

Part 1:

$W=FS$

$W=F_{_xs_x}+F{_ys_y}$

imagine the "i"and the "j" with the hat

$W=(10i-1j)(4i+3j)$

$W=(10*4)-(1*1)$

$W=40-1$

$W=39J$

Part 2:

$|F|=\sqrt{10^2+(-1)^2}$

$|F|=\sqrt{101}$

$|S|=\sqrt{4^2+1^2}$

$|S|=\sqrt{17}$

$W=|F||S|cos$ θ

$39=(\sqrt{101})(\sqrt{17} )cos$ θ

θ = $19.7$

Hope it helps

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