The power of the antenna is

and since the power is the emitted energy divided by the time, the energy emitted per second is

The frequency of the emitted photons is

So the energy of a single photon is

Therefore, to find the number of emitted photons per second, we should divide the total energy emitted by the antenna in 1 second by the energy of a single photon:
Answer:
C
Explanation:
When an object has a greater mass than the drag force pushing it back then it is moving forward therefore making car C faster than car D. If car D was much smaller it wouldn't have enough mass to push past the drag force.
Answer:
0.1 mm
Explanation:
if the diameter of a cylinder measured by vernier callipers the least count is 0.1 mm or equal to 2cm
Hope This Helped
Answer:
ответ 1.25 × 10‐³ и вот ваш ответ