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True [87]
3 years ago
15

A feeling of weightlessness in orbit is called

Chemistry
2 answers:
Serggg [28]3 years ago
8 0
Microgravity is your answer
Katen [24]3 years ago
6 0
A feeling of weightlessness in orbit is called microgravity.
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How many double bonds does CCL2H2 have?
galben [10]
None. Both chlorines and both hydrogens are single-bonded to the central carbon atom; the molecule is comprised of four single bonds and no double bonds.

Hope this helps!
4 0
2 years ago
If an atom has three shell and number of valence electrons are two. Is this element metal
cluponka [151]

Answer:

Metal

Element: Calcium

Valency: 2

Explanation:

To find the element, let's use the periodic table. (Look below)

We already went past 3 shells, just need the 2 electrons after it.

Just skip to the 4th row and count 2 to the right

We end up at Calcium.

Calcium is a metal and we're also on the alkaline earth metals column.

Calcium will need to lose 2 electrons to reach stability, so the valency is 2.

3 0
3 years ago
What is a property of covalent compounds
tensa zangetsu [6.8K]

C. low boiling points, since convalent bonds are comprise of two non metal elements, the have relatively low boiling points, since most of them are gases.

6 0
3 years ago
Read 2 more answers
I've been waiting for like 10 mins. Please answer this.
Degger [83]

The answer is B. 6CO2+H2O yields C6H12O6+ 6H20.

3 0
3 years ago
Read 2 more answers
A weather balloon is filled with helium that occupies a volume of 5.37 104 L at 0.995 atm and 32.0°C. After it is released, it r
svp [43]

Answer:

The new volume is 63583 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 5.37 * 10^4 L

The initial pressure = 0.995 atm

The initial temperature = 32.0 °C = 305.15 K

The pressure decreased to 0.720 atm

The temperature decreased to -11.7 °C = 261.45 K

Step 2: Calculate the new volume

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.995 atm

⇒with V1 = the initial volume = 5.37 *10^4 L

⇒with T1 = the initial temperature = 305.15 K

⇒with P2 = the decreased pressure = 0.720 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the decreased temperature : 261.45 K

(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45

V2 = 63583 L

The new volume is 63583 L

8 0
3 years ago
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