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ss7ja [257]
2 years ago
13

What speed must a 600 kg car have in order to have the same momentum as a 1200 kg truck traveling at a velocity of 10 m/s to the

west? 5 m/s west B 20 mls west 5 m/s east 20 m/s east
A) 5m/s west
B) 20m/s west
C) 5m/s east
D) 20m/s east
​
Physics
1 answer:
yKpoI14uk [10]2 years ago
4 0

Answer:

20 m/s

Explanation:

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Answer:

I think it is the forth one

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What happens when an object experiences friction?
kaheart [24]

Answer:Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.

Explanation:

Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.

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Imagine two fixed charges on the x axis. Charge one is +q and is located to the left of charge two which is equal to -4q. Where
givi [52]

Answer: B)To the left of the charges.

Explanation: between the charges the electric field will not cancel but will be added since electric field lines from both charges point in the same direction. To the right of the charge the -4q will take over as it’s strength overcomes the strength of the +q charge. At this point the magnitude of +q will never reach a magnitude strong enough to cancel the -4q. To the left, it is further away from -4q and is closer to +q and electric field lines point in different direction

7 0
2 years ago
Select the correct location on the image.
slega [8]

Answer:

orange line

Explanation:

it is the only straight line that makes sense. curved lines imply velocity changed. and the completly flat green line implies the vehicle didn't move since its position value stayed the same. must be the downward pointing orange line

8 0
2 years ago
You hold glider A of mass 0.125 kg and glider B of mass 0.375 kg at rest on an air track with a compressed spring of negligible
umka2103 [35]

Answer:

0.2 m/s

Explanation:

m_A = Mass of glider A= 0.125 kg

m_B = Mass of glider B = 0.375 kg

u_A = Initial Velocity of glider A = 0 m/s

u_B = Initial Velocity of glider B = 0 m/s

v_A = Final Velocity of glider A = 0.6 m/s

v_B = Final Velocity of glider B

As linear momentum is conserved

m_{A}u_{A}+m_{B}u_{B}=m_{A}v_{A}+m_{B}v_{B}\\\Rightarrow v_B=\frac{m_{A}u_{A}+m_{B}u_{B}-m_{A}v_{A}}{m_{B}}\\\Rightarrow v_b=\frac{0+0-0.125\times 0.6}{0.375}\\\Rightarrow v_b=-0.2\ m/s

Magnitude of the glider B at this time is 0.2 m/s

8 0
3 years ago
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