Most metamorphic processes takes place few kilometers below the Earth's surface. Thus, "metamorphic rocks" are formed under conditions found few kilometers under the Earth's surface.
Sedimentary rocks are formed by the compaction of sediments. Two main groups of sedimentary rocks are clastic sedimentary rocks and chemical sedimentary rocks.
Metamorphism refers to the changes in the mineral composition of the rocks. The three agents of metamorphism are heat, pressure and water.
The conversion of one form of rock to another is referred as rock cycle. In a rock cycle, an igneous rock formed from the deposition of molten magma can get converted into sedimentary rock when igneous rock breaks down into pieces and sediments. Finally, the any sedimentary rock or igneous rock can undergo metamorphosis to form metamorphic rocks. Metamorphic rock can again form igneous rock by melting of magma followed by crystallization.
If the number of rats decrease, snakes would look for another prey.
<u>Answer:</u> The percentage abundance of
and
isotopes are 75.77% and 24.23% respectively.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 34.9689 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 36.9659 amu
Fractional abundance of
isotope = 1 - x
- Average atomic mass of chlorine = 35.4527 amu
Putting values in equation 1, we get:
![35.4527=[(34.9689\times x)+(36.9659\times (1-x))]\\\\x=0.7577](https://tex.z-dn.net/?f=35.4527%3D%5B%2834.9689%5Ctimes%20x%29%2B%2836.9659%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.7577)
Percentage abundance of
isotope = 
Percentage abundance of
isotope = 
Hence, the percentage abundance of
and
isotopes are 75.77% and 24.23% respectively.
Answer:
a) 
b) 1657 €
Explanation:
Hola,
a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:

Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:


b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:

Con ello, los kilogramos de metano que cuestan 0,45 €:

Luego, aplicamos la regla de tres:
0.715 kg ⇒ 0.45 €
2630 kg ⇒ X
X = (2630 kg x 0.45 €) / 0.715 kg
X = 1657 €
Regards.